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fredd [130]
3 years ago
5

Help please algebra 8th grade need to finish ASAP!!

Mathematics
2 answers:
GenaCL600 [577]3 years ago
6 0
The answer is 56


hope this helps (:
igor_vitrenko [27]3 years ago
6 0
You would add 91+33 to get 124 and since all the angles in a triangle add up to 180 you would subtract 124 from 180 to get 56
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He first three terms of a geometric sequence are as follows. 10 , 30 , 90 find the next two terms of this sequence.+
ankoles [38]
10*3=30
30*3=90
90*3=270
270*3=810

or

10*3^1=30
10*3^2=90
10*3^3=270
10*3^4=810

the next two terms of this sequence are 270 and 810.
4 0
3 years ago
Use the given graph of f to state the value of each quantity, if it exists. (If an answer does not exist, enter DNE.)
alex41 [277]

Answer:

Hence the answer is given as follows,

Step-by-step explanation:

Graph of y = f(x) given,

(a) \lim_{x\rightarrow 2^{-}}f(x)=3

(b) \lim_{x\rightarrow 2^{+}}f(x)=1

(c) \lim_{x\rightarrow 2}f(x)= DNE \left \{ \therefore \lim_{x\rightarrow 2^{-}} f(x)\neq  \lim_{x\rightarrow 2^{+}}f(x) \right.

(d) f(2)=3

(e) \lim_{x\rightarrow 4}f(x) = 4

(f) f(4)= DNE.{ Hole in graph}

Hence solved.

3 0
3 years ago
Alonzo makes 8 dollars for each hour of work. Write an equation to represent his total pay p after working h hours.
Gnoma [55]

Answer:

25

Step-by-step explanation:

8 0
3 years ago
What is the difference between kilometers and kilograms?
Leona [35]
Kilometers is for distance, and kilograms is for solids
6 0
3 years ago
Read 2 more answers
April sold 75 tickets to the school Christmas play and collected $495. If adult tickets cost $8 and children tickets were $5 how
Ostrovityanka [42]

40 adult tickets were sold and 35 children tickets were sold

<em><u>Solution:</u></em>

Let "a" be the number of adult tickets sold

Let "c" be the number of children tickets sold

Cost of 1 adult ticket = $ 8

Cost of 1 children ticket = $ 5

<em><u>Given that April sold 75 tickets to the school Christmas play and collected $495</u></em>

Number of tickets sold = 75

number of adult tickets sold + number of children tickets sold = 75

a + c = 75 ----- eqn 1

<em><u>Given that April collected $495</u></em>

Thus we can frame a equation as:

number of adult tickets sold x Cost of 1 adult ticket + number of children tickets sold x Cost of 1 children ticket = $ 495

a \times 8 + c \times 5 = 495

8a + 5c = 495 ----- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>

From eqn 1,

a = 75 - c ---- eqn 3

Substitute eqn 3 in eqn 2

8(75 - c) + 5c = 495

600 - 8c + 5c = 495

-3c = 495 - 600

-3c = - 105

<h3>c = 35</h3>

Substitute c = 35 in eqn 3

a = 75 - 35

<h3>a = 40</h3>

Thus 40 adult tickets were sold and 35 children tickets were sold

8 0
3 years ago
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