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adelina 88 [10]
3 years ago
12

What is the area of a parallelogram whose vertices are A(-12,2) B(6,2) C(-2,-3, D(-20,-3)

Mathematics
1 answer:
butalik [34]3 years ago
6 0
C hope this helped :-) :-) :-) :-)
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Input, x 4 8 12 16 20 output y 21 37 53 69 85 what is the equation
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Answer:

The equation is y = 4x + 5

Step-by-step explanation:

To find the equation to this table, pick two ordered pairs and use the slope formula to find the slope. For this we'll use (4, 21) and (8, 37).

m(slope) = (y2 - y1)/(x2 - x1)

m = (37 - 21)(8 - 4)

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Elden [556K]

Given:

The figure of a construction.

To find:

The correct option that represents the given construction.

Solution:

In the given figure, the given angle is angle CAB.

The steps for the given figure are:

1. Draw a ray PQ.

2. Mark an arc BC on the given angle and mark the same arc on the line and the intersection of line and arc is point Q.

3. Set the compass of the length BA.

4. Put the compass on the point Q mark arc that intersect the first arc. The intersection of arcs is R.

5. Draw a ray PR.

These are the steps of construction to copy an angle.

Therefore, the correct option is A.

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