Answer: 24.49 or 24.5 if rounded.
Step-by-step explanation: We have to use the pythagorean theorem of course...
a² + b² = c²
15² + 20² = c²
225 + 400 = c²
600 = c²
c = 24.49 (If we round to the nearest tenth then the answer is 24.5)
Cubes have 6 numbers
3 odd, 3 even
probablity=desiredoutcome/totalpossibleoutcomes
there are 6 total desired outcomes (3 on each cube)
total possible, there are 6*6 or 36 total possible outcomes
so 6/36 or 1/6 chance
The limit does not exist. Why? Because the left hand limit DOES NOT equal the right hand limit. Let’s double check:
We could use -0.000001 to represent the left hand limit. This is less than 0. We plug in 5x - 8
5(-0.000001) - 8
-0.000005 - 8
-8.000005
If we would continue the limit (extend the zeros to infinity), we would get exactly
-8
That is our left hand limit.
Our right hand limit will be represented by 0.000001. This is greater than 0. We plug in abs(-4 - x)
abs(-4 - (0.000001))
abs(-4.000001)
4.000001
If we would continue the limit (extend the zeros to infinity), we would get exactly
4
4 does not equal -8, therefore
The limit does not exist
I would say its A but I'm not 100%
