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dlinn [17]
3 years ago
13

Johnny and Dawn were in a Math competition.

Mathematics
1 answer:
lukranit [14]3 years ago
5 0
The answer is d . 10b^2-25b .
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Silva set up a dog-walking business. He earned $60 in June. He is projected to earn 110% more in July. How much is Silva project
MissTica

Answer:

$126

Step-by-step explanation:

just used the calculator

4 0
3 years ago
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Jasmine is baking and selling cupcakes for $15 per dozen.She would like to make more than $120 in cupcake sales. Which number li
pishuonlain [190]

Answer:

Step-by-step explanation:

Jasmine is baking and selling cupcakes for $15 per dozen.

Let x be the number of dozens of cupcake made by Jasmine.

Her total sales= Sales Per Dozen X Number of Dozens of cupcake sold

= $15 X x = $15x

Since she would like to make more than $120 in cupcake sales.

It means her total sales must be greater than $120.

15x>120

x>120/15

x>8

The number line attached represents the solutions to the situation.

All integers to the right of 8 (excluding 8) satisfies the situation.

3 0
3 years ago
What would the domain and range of this graph be? In interval form, if it can be.
skad [1K]

Answer:

Step-by-step explanation:

Domain is the x values.  The interval of x-values that the function encompasses are from 0 inclusive to 7 exclusive.  In interval notation that is [0, 7).  The range is the y values.  The interval of y-values that the function encompasses are from what looks like -2 to 4.  In interval notation that is [-2, 4].  The domain goes from the lowest x-value to the highest; the range goes from the lowest y-value to the highest.

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3 years ago
(ANSWER ASAP) The table represents the multiplication of two binomials. What is the value of A?
PSYCHO15rus [73]
<h3>The value of A will be -3x^2 </h3>

By observing the table it can be concluded that the value of A must be equal to 3x × (-x)

So, the value will be -3x^2

4 0
3 years ago
For what value of c does x^2−2x−c=4 have exactly one real solution?<br> PLEASE HELP!!!!!!!
Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

x^2-2x-(c+4)=0.

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic ax^2+bx+d, the discriminant is \sqrt{b^2-4ad}.

(The discriminant is more commonly known as \sqrt{b^2-4ac}, but I changed the variable since we already have a c in the quadratic given.)

In the quadratic above, we have a=1, b=-2, and d=-(c+4). Plugging this into the formula for the discriminant, we have

\sqrt{(-2)^2-4(1)(-(c+4)).

Using the distributive property to expand and simplifying, the expression becomes

\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.

Setting the discriminant equal to 0 gives

2\sqrt{c+5}=0.

We can then solve the equation as usual: first, divide by 2 on both sides:

\sqrt{c+5}=0.

Squaring both sides gives

c+5=0,

and subtracting 5 from both sides, we have

\boxed{c=-5}.

3 0
2 years ago
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