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2 years ago

3/6x4/9 plz help meeeeee

Mathematics

2 answers:

disa [49]2 years ago

4 0

Answer:

2/9

Step-by-step explanation:

When multiplying fractions, you simply multiply straight across

3/6 × 4/9

(3 × 4 = 12) / (6 × 9 = 54)

= 12/54

= 2/9

Aleonysh [2.5K]2 years ago

3 0

Answer:

12/54

Step-by-step explanation:

4x3=12

6x9=54

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3 years ago

If multiplying by 1/4 makes a positive number smaller, then what dividing by 1/4 do to the value of the number? Explain your rea

mars1129 [50]

Answer:

It would quadruple it.

Step-by-step explanation:

When you divide by a fraction you first flip it then you multiply straight across. For example 3 / (1/4) you flip then multiply which gives you 3/1 * 4/1 = 12/1 which simplifies to 12

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2 years ago

Help! open the attachment below!

gregori [183]

Answer:

yes it is

Step-by-step explanation:X=side lenghths 2/3

Y=perimeter 12/18

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2/6 and 3/6 i beleve i need a lil more info

6 0

2 years ago

HELP!! What is the equation of the graphed line?<br> (y=mx+b)

Anettt [7]

So to fine slope you would use the formula down below:

rise/run

So use a graphed point, 0, -5 and you rise or count up quadrants up to a point and then horizontally move to when you find that point.

So from 0,-5 go up 9 vertically, and you would be on the 4

Go horizontal 3 spots and your on a designated point.

So the rise is four and the run is 3

So 4/3 is the slope

In the y= Mx + b equation you would set the equation like this:

y= 4/3 + -5

The m in this formula stands for the slop and the b stands for the y-intercept

The y-intercept is the point that is on the y-axis and where it starts.

6 0

1 year ago

A ferry will safely accommodate 82 tons of passenger cars. Assume that the meanweight of a passenger car is 2 tons with standard

Shalnov [3]

Answer:

The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.

Step-by-step explanation:

Given:

Maximum safe-weight of 37 cars = 82 tons

∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)

Mean weight of 1 car (μ) = 2 tons

Standard deviation of 37 cars = 0.8 tons

So, standard deviation of 1 car is given as:

$\sigma=\frac{0.8}{\sqrt{37}}=0.13$

Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?

The sample is normally distributed (Assume)

Now, let us determine the z-score of the mean weight.

The z-score is given as:

$z=\frac{x-\mu}{\sigma}\\\\z=\frac{2.22-2}{0.13}\\\\z=\frac{0.22}{0.13}=1.69$

Now, finding P(x > 2.22) is same as finding P(z > 1.69).

From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.

But we need the area under the curve for z > 1.69.

So, we subtract from the total area. Total area is 1 or 100%.

So, $P(z > 1.69) = 1 - P(z < 1.69)$

$P(z>1.69)=1-0.9545=0.0455\ or\ 4.55\%$

Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.

8 0

3 years ago