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a_sh-v [17]
3 years ago
15

The table shows the different packs of sports cards available for purchase. What is the smallest number of baseball and football

cards that Herb can buy so that he will have the same number of each type of card?
Game
Number of Cards per pack
Baseball
40
Hockey
35
Football
14
Mathematics
2 answers:
maks197457 [2]3 years ago
7 0
Least common multiple would be 280 

WARRIOR [948]3 years ago
5 0
<span>The least common multiple would be 280 cards of each. 

20 Packs of football, 8 packs of Hockey, and 7 packs of Baseball.</span>
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Answer:

Volume = 150 m^2

Step-by-step explanation:

Using Volume formula of prism, we get L*W*H, but since we know the area of the base is L*W, which is 12.5, we multiply 12.5 by 12 to get 150 m^2.

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A rectangular room is 12 1/2 feet long and 10 1/3 feet wide. what is the area of the room
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Step-by-step explanation:

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The dimensions of a 4-in. square are multiplied by 3. How is the area affected? {Show work!}
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In Grafton, a rural area in Vermont, the distance (in meters) between telephone poles has a uniform distribution between 40 and
coldgirl [10]

Answer:

a) 60% probability that the distance is environment friendly.

b) The mean of the distances between the telephone poles is 52.5 meters.

c) The standard deviation of the distance between the telephone poles is 7.22 meters.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

P(X \leq x) = \frac{x - a}{b-a}

Uniform distribution between 40 and 65 meters.

This means that a = 40, b = 65

a) Any distance between poles greater than 50 meters is considered to be environment friendly. What is the probability that the distance is environment friendly?

This is P(X > 50)

We have that

P(X \leq 50) + P(X > 50) = 1

So

P(X > 50) =  1 - P(X \leq 50)

P(X \leq 50) = \frac{50 - 40}{65 - 40} = 0.4

P(X > 50) =  1 - P(X \leq 50) = 1 - 0.4 = 0.6

60% probability that the distance is environment friendly.

b) Find the mean of the distances between the telephone poles

The mean of the uniform distribution is

M = \frac{a + b}{2}

So

M = \frac{a + b}{2} = \frac{40 + 65}{2} = 52.5

c) Find the standard deviation of the distance between the telephone poles.

The standard deviation of the uniform distribution is:

S = \sqrt{\frac{(b-a)^{2}}{12}}

So

S = \sqrt{\frac{(65-40)^{2}}{12}} = 7.22

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