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Karolina [17]
4 years ago
14

Write 0.00147 in standard form

Mathematics
2 answers:
tekilochka [14]4 years ago
5 0
Hey

0.00147 = 147 / 100000
tangare [24]4 years ago
4 0
0.00147 in standard form would be 147/100000  scientific form would be 1.47*10^-3 

hope this helps! Thank you! Any questions please ask!
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If line segment ab=7cm draw a perpendicular at a point c on line ab such the ac=3.5cm
Reil [10]

See attachment for the drawing of the perpendicular at a point c on line ab such the ac = 3.5 cm

<h3>How to draw the perpendicular at a point c on line ab such the ac = 3.5 cm?</h3>

The given parameters are:

Length of segment AB = 7 cm

Also, we have:

Point C is located on line segment AB

This means that:

Length of segment AC = Length of segment BC = 3.5 cm

When represented on a line segment, we have:

A          C          B

See attachment for the drawing of the perpendicular at a point c on line ab such the ac = 3.5 cm

Read more about perpendicular line at:

brainly.com/question/1865107

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6 0
2 years ago
What is the solution to 5x - 3 = 12SHOW YOUR WORK
Dafna1 [17]

Answer:

Answer =  X= 3

Step-by-step explanation:

Let's solve your equation step-by-step.

5x − 3 = 12

Step 1: Add 3 to both sides.

5x − 3 + 3 = 12 + 3

5x = 15

Step 2: Divide both sides by 5.

5x/5 = 15/5

Answer = X= 3



Hope I Helped. Have A Wonderful Day...


3 0
3 years ago
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Mariulka [41]

Answer: 3900\pi ft^3

if you use the formula on how to find the volume of a cone

V=\pir^2*h/3

you will insert 30 where the r is, 13 in where h is, after you just solve that and your answer would be 3900\pi ft^3

3 0
3 years ago
A Teenager can wash two tables per minute write an expression for how many tables they can wash in M minutes
Vikki [24]
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3 years ago
Which is traveling faster, a car whose velocity vector is 201 + 25), or a car whose velocity vector is 30i, assuming that the un
Snowcat [4.5K]

Answer:

2nd car is running faster than the first car by 2.01 units.

Step-by-step explanation:

Let's assume that

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v_1\ =\ 20i\ +\ 25j

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v_2\ =\ 30i

=> speed of first car,

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       =\ \sqrt{1025}

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u_2\ =\ \sqrt{(30)^2+(0)^2}

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u_2\ -\ u_1\ =\ 32.01\ -30

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Hence, 2nd car is running faster than the first car by 2.01 units.

8 0
3 years ago
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