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cluponka [151]
4 years ago
14

A random variable X follows the uniform distribution with a lower limit of 720 and an upper limit of 920. a. Calculate the mean

and the standard deviation for the distribution. (Round intermediate calculation for standard deviation to 4 decimal places and final answer to 2 decimal places.) b. What is the probability that X is less than 870?
Mathematics
1 answer:
MariettaO [177]4 years ago
7 0

Answer:

a. mean = 820; standard deviation = 57.74

b.0.75 or 75%

Step-by-step explanation:

Lower limit (L) = 720

Upper limit (U) =920

a.The mean of an uniform distribution is given by:

\mu = \frac{L+U}{2}=\frac{720+920}{2}\\ \mu = 820

The standard deviation of an uniform distribution is given by:

\sigma = \frac{U-L}{\sqrt{12}} = \frac{920-720}{\sqrt{12}}\\\sigma=57.74

b. The probaility that X is less 870 is:

P(X

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