Answer:
72 percent of the total houses are small
Step-by-step explanation:
The first step is to know the total apartments from the ratio: This is got by adding 18 + 7 = 25
The ratio of small apartments to regular ones is 18:7
To get the percentage that is small, we have to express the number of small houses when compared to the total available apartments. (<em>Note: not the regular ones) </em>as a percentage.
This will be (18/25) X 100 = 72%
Therefore, 72 percent of the total houses are small
Answer:
1-9 answers
Step-by-step explanation:
1=-38
2=-25
3=16
4=-4
5=0
6=-34
7=9
8=-7
9=-4
I have seen this question before and I think you meant 10 more dimes than nickels.
We can use substitution to answer this question. The value of a nickel is 5 cents, and we can use the variable n to represent the number of nickels. The value of a dime is 10 cents, and we can use the variable d to represent the number of dimes.
First lets figure out the equations.
.10d+.5n=2.80 (the number of nickels (n) multiplied by .5 will tell us their money value. Same thing for the dimes)
d-n=10 (since there are 13 more dimes than nickels, the number of dimes value (d) minus the number of nickels value (n) will give us 10)
Now lets isolate a variable in one of the equations, preferably the second one because it doesn't have any visible coefficients,
d-n=10
-n=10-d (subtracted the d from both sides)
n=-10+d (made the n positive)
Now that we have the value of n, we can plug it into the other equation.
.10d+.05n=2.80
.10d+.05(-10+d)=2.80 (we replaced the n with the value that we previously got)
.10d-.5+.05d=2.80 (did the multiplication)
.15d-.5=2.80 (combined like terms)
.15d=3.30 (added the .5 to both sides)
d=22 (divided both sides by the .15)
Now that we know that there are 22 dimes and we also know that there are 10 less nickels than dimes, so we can subtract 10 from 22 to get the number of nickels. 22-10=12
d=22
n=12
Find out what number times it's self equals the number you need to find the square root of and that's the square root
33117.7 in is the answer I believe…
