By the polynomial remainder theorem, the remainder upon dividing

by

will be the value of

.
... | 1 ... -6 ... -4 ... -6 .... -2
3. | .. ... 3 ... -9 ... -39 .. -135
--------------------------------------
... | 1 ... -3 ... -13 . -45 .. -137
So you have

which means

.
Answer:
<em>Value</em><em> </em><em>of</em><em> </em><em>p</em><em> </em><em>is</em><em> </em><em>14</em>
Step-by-step explanation:

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Answer:
Step-by-step explanation:
Part 1:
Let
Q₁ = Amount of the drug in the body after the first dose.
Q₂ = 250 mg
As we know that after 12 hours about 4% of the drug is still present in the body.
For Q₂,
we get:
Q₂ = 4% of Q₁ + 250
= (0.04 × 250) + 250
= 10 + 250
= 260 mg
Therefore, after the second dose, 260 mg of the drug is present in the body.
Now, for Q₃ :
We get;
Q₃ = 4% of Q2 + 250
= 0.04 × 260 + 250
= 10.4 + 250
= 260.4
For Q₄,
We get;
Q₄ = 4% of Q₃ + 250
= 0.04 × 260.4 + 250
= 10.416 + 250
= 260.416
Part 2:
To find out how large that amount is, we have to find Q₄₀.
Using the similar pattern
for Q₄₀,
We get;
Q₄₀ = 250 + 250 × (0.04)¹ + 250 × (0.04)² + 250 × (0.04)³⁹
Taking 250 as common;
Q₄₀ = 250 (1 + 0.04 + 0.042 + ⋯ + 0.0439)
= 2501 − 0.04401 − 0.04
Q₄₀ = 260.4167
Hence, The greatest amount of antibiotics in Susan’s body is 260.4167 mg.
Part 3:
From the previous 2 components of the matter, we all know that the best quantity of the antibiotic in Susan's body is regarding 260.4167 mg and it'll occur right once she has taken the last dose. However, we have a tendency to see that already once the fourth dose she had 260.416 mg of the drug in her system, that is simply insignificantly smaller. thus we will say that beginning on the second day of treatment, double every day there'll be regarding 260.416 mg of the antibiotic in her body. Over the course of the subsequent twelve hours {the quantity|the quantity|the number} of the drug can decrease to 4% of the most amount, that is 10.4166 mg. Then the cycle can repeat.
Answer:
See explanation below.
Step-by-step explanation:
The scale factor can be found by dividing two corresponding side lengths. For instance, if you have two triangles, divide the new length of the larger or smaller triangle by the same side length of the original.
If the side length of the new was 9 and the old was 3 then the scale factor would be 9/3 = 3.
If it were flipped then the new would be 3 and the old would be 9. So the scale factor would be 3/9 = 1/3.
Answer:
After reflection over the x-axis, we have the coordinates as follows;
A’ (5,-2)
B’ ( 1,-2)
C’ (3,-6)
Step-by-step explanation:
Here, we want to find the coordinates A’ B’ and C’ after a reflection over the x-axis
By reflecting over the x-axis, the y-coordinate is bound to change in sign
So if we have a Point (x,y) and we reflect over the x-axis, the image of the point after reflection would turn to (x,-y)
We simply go on to negate the value of the y-coordinate
Mathematically if we apply these to the given points, what we get are the following;
A’ (5,-2)
B’ ( 1,-2)
C’ (3,-6)