3x - 6 _____ x - 2 ?????????

1 answer:

6 0

Answer: The expression given simplifies to: 3 .
_________________________________________________
Explanation:
________________________________________________
Given: (3x - 6) / (x-2) ;
___________________________
Factor the numerator into: 3(x-2).
________________________________
Now, rewrite the expression as:
____________________________
$\frac{3(x-2)}{(x-2)}$ ;
________________________________________
The "(x - 2)" values cancel to "1" ; since "(x - 2) ÷ (x - 2) = 1" ;
_______________________________________________________
and we are left with: "3 ".
________________________________

You might be interested in

What is greater than 525.06 but less than 525.6?

Ivanshal [37]

Answer:

Step-by-step explanation:

4 0

3 years ago

Solve the equation using the method that seems appropriate.

Lera25 [3.4K]

The answer is x=-5.5 . 2x-3 = 4x+8 . subtract 2x from both sides and then subtract 8 from both sides and get -11=2x . then divide both sides by 2 to get . -5.5=x

8 0

3 years ago

An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s

Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, $s=120\ ft/s$

The height 'h' of the debris above the ground is given as:

$h(t)=-16t^2+120t$

As per question, $h(t)=56\ ft$ . Therefore,

$56=-16t^2+120t$

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

$-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0$

Using quadratic formula to solve for 't', we get:

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s$