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vodomira [7]
3 years ago
5

A tester sets 99% confidence limits on a certain statistic. The absolute difference between either limit and the mean is an exam

ple of:
Mathematics
2 answers:
Marta_Voda [28]3 years ago
5 0

Answer:

Margin of error.

Step-by-step explanation:

Given that a tester sets 99% confiidence limits on a certain statistic

A confidence limit for 99% is obtained as

lower bound of confidence interval as Mean - critical 99% *std error and

upper bound of confidence interval as Mean + critical 99% * std error

Thus a confidence interval would be in interval form with lower limit and upper limit and the average of these two limits is the mean.

The absolute difference between either limit and the mean is the value

Critical value for 99% multiplied by Std error of the variable

= Margin of error

Hence answer is margin of error

solmaris [256]3 years ago
3 0
I found the missing choices:
<span>the standard deviation
the margin of error
the variance
the population mean
</span>
<span>The absolute difference between either limit and the mean is an example of THE VARIANCE.

Variance is defined as the</span><span> average of the </span>squared<span> differences from the Mean. </span>
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The total cost includes the setup cost + per hour cost.

Let, x represents the time and y represents the total cost.

y=200+75x .... (1)

Let Y represent the cost for B's DJ service.

y=125x .... (2)

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b. Substitution Method.

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c. Addition method.

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For x = 6 hours, equation (1)

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Question is not complete and so I have attached the complete question.

Answer:

C: f(x) = -½x + 4

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