Answer:
Step-by-step explanation:
Let's first put that polynomial in standard form by descending powers of t:
![h(t)=-5t^2+54t](https://tex.z-dn.net/?f=h%28t%29%3D-5t%5E2%2B54t)
If we are looking for the times where the rocket is at a height of 26 m, we sub in a 26 for h(t) and factor to solve for t. First we get all the terms on one side of the equals sign and set it equal to zero.
![-5t^2+54t-26=0](https://tex.z-dn.net/?f=-5t%5E2%2B54t-26%3D0)
That is a second degree polynomial so you can factor it however you are most comfortable to get the values of t are:
t = .51 sec and t = 10.29 sec
Since this is a polynomial, there will be 2 values of t for this time with y being the height and x being the time. The parabola is symmetrical about the vertex so there are 2 values of t (or x) that equal height (or y).
Answer:
(3,3)
Step-by-step explanation:
D is on (1,1) so times by k which is 3 = (3,3)
Answer:
THank you. THe answer is a scalene acute triangle.
Step-by-step explanation: None of the sides are congruent and none of the angles are above 90 degrees.
8 and 1/8 are good so that would be the answer