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True [87]
3 years ago
9

Please help me with this math problem.Evalaute 7r - 5/s when r= 3 and s= 5.

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
7 0

20 is the answer 7(3)-5/(5)=20

JulijaS [17]3 years ago
5 0

Rewrite the equation: 7(3)-5/5

Evaluate.

21-1=20

20 is your answer.

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⇒ Based on the given rules of "Fire-Water-Sponge," outcomes 1<span>, </span>5<span>, and </span>8 are outcomes where you lose.

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Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).
storchak [24]

Answer:

P=16.53\ units

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(2-2)^{2}}

d=\sqrt{(-1)^{2}+(0)^{2}}

d=\sqrt{1}

dPQ=1\ unit

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}

d=\sqrt{(-5)^{2}+(-4)^{2}}

dQR=\sqrt{41}\ units

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

d=\sqrt{(3+2)^{2}+(-2+2)^{2}}

d=\sqrt{(5)^{2}+(0)^{2}}

dRS=5\ units

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-1)^{2}+(-4)^{2}}

dPS=\sqrt{17}\ units

step 5

Find the perimeter

P=PQ+QR+RS+PS

substitute the values

P=1+\sqrt{41}+5+\sqrt{17}

P=6+\sqrt{41}+\sqrt{17}

P=16.53\ units

5 0
3 years ago
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