Question

What is the probability that the first die will have ""a natural number greater than 1 which can only be divisible by 1 and itself""? (4 points)

Answer 1

Answer:

The probability that the first die will have ""a natural number greater than 1 which can only be divisible by 1 and itself = 0.5

Step-by-step explanation:

A die has 6 faces with the following sample spaces 1, 2, 3, 4, 5 and 6

Then, a natural number greater than 1 which can only be divisible by 1 and itself is the definition of a prime number.

The prime numbers in the sample space are 2, 3 and 5

So, probability of getting a prime number in the sample space, P(prime numbers) = n(prime numbers)/[n(sample space)] = 3/6 = 1/2 = 0.5