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2 years ago

Please solve both, graph and show work. answer also has to be in y=mx+b format.

Mathematics

1 answer:

hammer [34]2 years ago

7 0

To solve both it is (1,1). I'm not sure how to write the answer in y=mx+b format, but I made a graph using desmos.com if that helps.

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The number of a particular fish in thousands x years after 1972 can be modeled by f(x)=230(0.886)x. Estimate the year when the n

sashaice [31]

Answer:

The year is 1979.

Step-by-step explanation:

Given:

The function relating fish population and number of years since 1972 is:

$f(x)=230(0.886)^x\\Where,\ f(x)\rightarrow \textrm{fish population}\\x\rightarrow \textrm{number of years passed after 1972}$

Now, when the fish population reaches 99 thousand, it means that $f(x)=99$ . Now, plugging in $f(x)=99$ in the above equation and solving for $x$ . This gives,

$99=230(0.886)^x\\\frac{99}{230}=0.886^x\\\\\textrm{Taking natural log on both sides}\\\ln(0.886)^x=\ln(\frac{99}{230})\\\\\textrm{Using log property: }\log a^b=b\log a\\x\ln (0.886)=\ln(0.43)\\x\times (-0.12)=-0.84\\x=\frac{-0.84}{-0.12}=7\ years$

Therefore, the year after 7 years passed since 1972 is given as:

1972 + 7 = 1979.

So, the year when the number of fish reaches 99 thousand is 1979.

8 0

2 years ago

I need some help with solving inequalitys 9x-9 greater thab or equal to 2(8x-15)

leonid [27]

Simplify 2(8x-15) first

7 0

2 years ago

What is the value of y in the following system of equations? explain how you found your answer

AlekseyPX

Step-by-step explanation:

I've used elimination method over here but it can also be done by using substitution.

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2 years ago

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In 30 seconds, 2-year-old Janay's heart beats 36 times.

skelet666 [1.2K]

Answer: 144 beats

Step-by-step explanation

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2 years ago

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What is 252 = 11n + 10

xz_007 [3.2K]

Answer:

n=22 or 252=11(22)+10

Step-by-step explanation: 252=11n+10. Start by attempting to isolate the varyable by subracting 10 from both sides--> 242=11n, divide by 11--> 22=n

PROOF 252=11*22+10=242+10=252

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2 years ago

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