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Harlamova29_29 [7]
3 years ago
12

Please helpA) x= -4 and 4B) x=4 and 6C) x=2 and 8D) no solution

Mathematics
1 answer:
Neporo4naja [7]3 years ago
4 0

Answer:

No solutions

Step-by-step explanation:

|-2x-10| + 4 = 2

Subtract 4 from each side

|-2x-10| + 4-4 = 2-4

|-2x-10|  = -2

The absolute value is negative so there are no solutions.

Absolute values are always positive, so they cannot be negative.


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Twice the difference of a number 8 equals 5
-Dominant- [34]

Answer:

2(n-8) = 5

Step-by-step explanation:

I'm assuming that its supposed to say "a number <em>and</em> 8"

6 0
2 years ago
Read 2 more answers
Max has a science test on Thursday. On Monday he studied 2/9 of the material. On Tuesday he studied 1/4 of the remaining materia
wolverine [178]

Answer:

The answer to your question is:

Fraction he has review =  17/36

Fraction he have to study = 19/36

Step-by-step explanation:

Data

Monday studied = 2/9

Tuesday = 1/4

Fraction he has review = ?

Fraction he has left = ?

Process

As the denominator is 9, consider the whole is 9.

Then:    Fraction left on Monday = 9/9 - 2/9

                                                      = 7 / 9

Fraction left on Tuesday = 7/9 - 1/4

                                         = (28 - 9) / 36

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Fraction he has review =  17/36

Fraction he have to study = 19/36

3 0
3 years ago
Write an explicit rule in function form for the sequence represented by the given terms.
hram777 [196]

Answer:

The general relation about a geoemtric sequence is

a_{n}=a_{1}r^{n-1}

For the first sequence, we have

3=a_{1}r^{5-1}

147=a_{1}r^{7-1}

Which is a system of equations. We can isolate a variable in the first equation to replace that expression into the second equation.

a_{1}=\frac{3}{r^{4} }

147=\frac{3}{r^{4}  }r^{6}

r^{2}=\frac{147}{3}\\  r=\sqrt[2]{49}\\r=7

Now, we replace this value to find the other one

3=a_{1}(7)^{4}\\ a_{1}=\frac{3}{2401}

Therefore, the explicit rule function is

a_{n}=\frac{3}{2401}  \times (7)^{n-1}

Now, we use the same process for the second sequence.

10=a_{1}r^{3-1}  \\a_{1}=\frac{10}{r^{2} }

The second equation is

1440=a_{1}r^{5-1}\\a_{1}=\frac{1440}{r^{4} }

Now, we solve the following expression

\frac{10}{r^{2} }=\frac{1440}{r^{4} }

We solve for r

\frac{r^{4} }{r^{2} }=\frac{1440}{10}\\r^{2}=144\\ r=\sqrt{144} \\r=12

Then

a_{1}=\frac{10}{(12)^{2} }  =\frac{10}{144}=\frac{5}{72}

Therefore, the function that models the second sequence is

a_{n}=\frac{5}{72} \times (12)^{n-1}

Notice that a_{n} is the dependent variable and n is the independent variable.

5 0
3 years ago
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Answer:

Step-by-step explanation:

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Answer:

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degrees of freedom= 12-2=10

at α=.025 from t table

p value= 2.228

6 0
3 years ago
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