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Ivahew [28]
2 years ago
13

A number is greater than another number by 5. if their sum is 21, find the number​

Mathematics
2 answers:
DochEvi [55]2 years ago
6 0

Answer:

x=13

y=8

Step-by-step explanation:

let the greater number be x and the smaller number be y.

<u>Now</u><u>,</u>

from first condition,

x = y + 5 --------1

from second condition,

x + y = 21

or, x = 21 - y --------2

from equation 1 and 2,

y + 5 = 21 - y

or, 2y = 16

y = 8

now,

putting the value of y in equation 1

x = 8 + 5

= 13

Flura [38]2 years ago
5 0

Answer:

13.

Step-by-step explanation:

x+x+5=21

2x+5=21

2x=16

x=8

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X+24=35 how to solve this
timama [110]

Answer:

X = 11

Step-by-step explanation:

Simplifying

X + 24 = 35

Reorder the terms:

24 + X = 35

Solving

24 + X = 35

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-24' to each side of the equation.

24 + -24 + X = 35 + -24

Combine like terms: 24 + -24 = 0

0 + X = 35 + -24

X = 35 + -24

Combine like terms: 35 + -24 = 11

X = 11

Simplifying

X = 11

8 0
2 years ago
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A local pizzeria offers 11 toppings for their pizzas and you can choose any 4 of them for one fixed price. How many different ty
choli [55]
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5 0
3 years ago
EASY POINTS:
iVinArrow [24]

Answer: -750ft

Step-by-step explanation: -450+-300=-750

3 0
2 years ago
Read 2 more answers
(10.02)
melisa1 [442]

Answer:

sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}

Therefore:

sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}

cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}

Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}

4 0
3 years ago
Mr. Schordine wants to fill up enough helium balloons to allow him to fly through the skies. He weighs 84 kilograms. He knows th
Cerrena [4.2K]

Answer:

There is needed around 311 balloons to fulfill Mr. Schordine’s dream of flight.

Step-by-step explanation:

First, we need to calculate the volume of each balloon by considering the balloons as a sphere:    

V = \frac{4}{3}\pi r^{3}

Where:

r: is the radius = 0.4 meters

V = \frac{4}{3}\pi r^{3} = \frac{4}{3}\pi (0.4 m)^{3} = 0.27 m^{3}

Knowing that 1 m³ of helium is able to lift about 1 kg, that Mr. Schordine weights 84 kg, and that each ballon has 0.27 m³ of helium, the number of balloons needed are:

N = \frac{1 m^{3}}{1 kg}*84 kg*\frac{1 balloon}{0.27 m^{3}} = 311.1 \: balloon              

Therefore, there is needed around 311 balloons to fulfill Mr. Schordine’s dream of flight.      

 

I hope it helps you!

6 0
3 years ago
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