All categories

2 years ago

What is the average of the following numbers 66.9,5.6,70.1

Mathematics

1 answer:

nydimaria [60]2 years ago

8 0

Answer:

47.53

Step-by-step explanation:

First you add all of the numbers together.

66.9+5.6+70.1=142.6

Then you divide the sum of numbers by how many number there are.

142.6/3=47.53

You might be interested in

Which could be the base shape of the cylinder

olga_2 [115]

Answer: i think it is a circle

Step-by-step explanation: because on the top and bottom its circle

5 0

2 years ago

Read 2 more answers

Wyatt has 32 marbles in his collection. Twenty of his marbles are red, four are blue, and the

dmitriy555 [2]

Answer:

6 and 2/5

Step-by-step explanation:

20% of 32 is 6.4

4 0

2 years ago

Which property of soil depends on the size of particles?

seropon [69]

The property of soils which depends on the size of particles is Texture.

<h3>Properties of Soil</h3>

The properties of Soil include colour, odor, temperature, and texture as measured by porosity, mouldability and a host of other texture effects.

It is evident that the texture of soil is dependent on the size of the particles as it affects how packed the particles of the soil is.

Read more on properties of soil;

brainly.com/question/26462165

4 0

2 years ago

Least to greatest 87% 0.432 2/8

Scorpion4ik [409]

Answer: 2/8, 0.432, 87%

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Radioactive Waste The rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt,

Dmitry_Shevchenko [17]

Answer:

$\displaystyle{\int^{\infty}_0 {50e^{-0.04t}}\, dt}=1250$

Step-by-step explanation:

Given:

$T =\displaystyle{\int^{\infty}_0 {Pe^{-kt}} \, dt}$

where,

T = total amount of waste

P = 50, the initial rate

k = 0.04

t = time

$T =\displaystyle{\int^{\infty}_0 {50e^{-0.04t}} \, dt}$

now we need to solve this integral!

$T =\displaystyle{50\int^{\infty}_0 {e^{-0.04t}} \, dt}$

$T = \left|50\left(\dfrac{e^{-0.04t}}{-0.04}\right)\right|^{\infty}_0$

$T = \left|-1250e^{-0.04t}\right|^{\infty}_0$

$T = (-1250e^{-0.04(\infty)})-(-1250e^{-0.04(0)})$

when any number has a power of negative infinity it is 0. because: $a^-{\infty} = \dfrac{1}{a^{\infty}} = \dfrac{1}{\infty} = 0$ , like something being divided by a very large number!

$T = (-1250(0))-(-1250e^0)$

$T = 1250$

this is the total amount of waste

6 0

2 years ago

What is the average of the following numbers 66.9,5.6,70.1​

What is the average of the following numbers 66.9,5.6,70.1