Given the functions
(a) f(x) = x³ + 5x² + x
(b) f(x) = x² + x
(c) f(x) = -x
Function (a)
f(-x) = (-x)³ + 5(-x)² + (-x)
= -x³ + 5x² - x
= -(x³ - 5x² + x)
The function is neither even nor odd.
Function (b)
f(-x) = (-x)² + (-x)
= -(-x² + x)
The function is neither even nor odd.
Function (c)
f(-x) = -(-x)
= x
= -f(x)
Because f(-x) = -f(x) the function is odd.
Answer: f(x) = -x is an odd function.
Y ≥ -3x + 2
It will be good to draw a graph and read the solution from the graph
y = -3x + 2
for x = 0 → y = -3 · 0 + 2 = 2 → (0, 2)
for x = 2 → y = -3 · 2 + 2 = -6 + 2 = -4 → (2, -4)
Answer: A, C, E, F.
Step-by-step explanation:
yes, if your teacher meant to include the default factors of every positive integer number : 1 and the number itself.
these are the 2 positive integer factors.
if a positive number can only be divided without remainder by 1 or by itself (with result 1), then it is per definition a prime number.
if the number can be divided without remainder by another number, then we are not dealing with a prime number.
but if your teacher did not have these default factors in mind, then no :
example : 15
15 has only 2 factors : 3 and 5.
both are positive integer numbers.
and yet 15 is not a prime number.
but back to my first point, 15 also has formally the factors 1 and 15. so, if we count them too, then we have suddenly 4 factors. and the original statement fits again.
Ratio is used 4:1 for the table that has 2 sides
Answer:
660.5
Step-by-step explanation:
