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3 years ago

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What is the length of leg s of the triangle below?

1 answer:

maks197457 [2]3 years ago

4 0

Answer:

What is the length of leg s of the triangle below?

B. atau F

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HELP ME PLEASE IM BEGGING YOU

WITCHER [35]

Answer:

Parallel

Step-by-step explanation:

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3 years ago

What is the radius of this circle?

ale4655 [162]

Answer: the answer is 7cm

Step-by-step explanation:if the diameter is 14, just do 14/2=7

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2 years ago

Can you help prove this identity?

mario62 [17]

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3 years ago

Solve for x<br> (1/x) -2/3 = (4x)

Vadim26 [7]

The value of x is $x=\frac{-1+\sqrt{37}}{12}$ and $x=\frac{-1-\sqrt{37}}{12}$

Step-by-step explanation:

The equation is $\frac{1}{x}-\frac{2}{3}=4 x$

Subtracting by $4x$ on both sides,

$\frac{1}{x}-\frac{2}{3}-4 x=0$

Taking LCM,

$\frac{3-12 x^{2}-2 x}{3 x}=0$

Multiplying by 3x on both sides,

$-12 x^{2}-2 x+3=0$

Dividing by (-) on both sides,

$12 x^{2}+2 x-3=0$

Using quadratic formula, we can solve for x.

$\begin{aligned}x &=\frac{-2 \pm \sqrt{2^{2}-4 \cdot 12 \cdot(-3)}}{2 \cdot 12} \\&=\frac{-2 \pm \sqrt{4+144}}{2 \cdot 144} \\&=\frac{-2 \pm \sqrt{148}}{24} \\&=\frac{-2 \pm 2 \sqrt{37}}{24}\end{aligned}$

Taking out common term 2, we get,

$\begin{array}{l}{x=\frac{-2(1 \pm \sqrt{37})}{24}} \\{x=\frac{-1 \pm \sqrt{37}}{12}}\end{array}$

Thus, the value of x is $x=\frac{-1+\sqrt{37}}{12}$ and $x=\frac{-1-\sqrt{37}}{12}$

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3 years ago

Help plz plz plz plz .

nikklg [1K]

The y intercept is where the line hits the verticals line of the graph. Hope this helps!

7 0

3 years ago