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Aleks [24]
3 years ago
7

A fair spinner is divided into 3 equal sections : red blue and green, it is spun 5 times what is the probability of getting red

twice
Mathematics
1 answer:
Sav [38]3 years ago
5 0

Answer:

80/243

or

.329218107

Step-by-step explanation:

This is a binomial distribtuion

THe probability of red= 1/3

the probability of not red= 2/3

Probability of getting exactly 2 reds in 5 spins

{5\choose2}*\frac{1}{3}^2*\frac{2}{3}^3=.329218107

or

80/243

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2 years ago
What is the solution of the system? Use elimination. 7x + 5y = 19 −7x − 2y = −16
netineya [11]

Make the coefficient of y the same in both equations:

To do this, multiply equation one by 2, and equation two by 5 (this will make the coefficient 10 in both).

14x + 10y = 38
-35x - 10y = -80


Eliminate the y variable by adding the equations from each other

   (14x + 10y = 38)
+ (-35x - 10y = -80)
=  -21x +  0y  = -42

We now have -21x = -42. The y variable has been eliminated.


Solve for x

-21x = -42

Divide both sides by -21 to get x on its own.

x = 2


Substitute x into the equation to find y.

7*2+5y=19

14+5y=19

Subtract 14 from both sides.

5y=19-14

5y=5

Divide by 5 on both sides to get y on its own.

y=5/5

y=1


The answer is (2,1)


8 0
3 years ago
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Answer:

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Step-by-step explanation:

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