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djverab [1.8K]
3 years ago
6

Use the following graph below , select all Statements that are true Please and thank you

Mathematics
1 answer:
Marizza181 [45]3 years ago
6 0

we will select each options and then we verify it

(a)

since, this is greatest integer function

so, it's value will be equal to lesser integer value

so,

f(4.9)=4

so, this is FALSE

(b)

since, this is greatest integer function

so, it's value will be equal to lesser integer value

so,

f(-3.4)=-4

so, this is TRUE

(C)

This is FALSE

(D)

This is TRUE

(E)

Since, it does not satisfy horizontal line test

so, it is not one to one

so, this is FALSE

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What is the value of 2x3 + 4x2 - 3x2 - 6x when x = 3?
never [62]

Answer:

-10

Step-by-step explanation:

If the equation is 2 x 3+4 x 2-3 x 2- 6(x)=  .  Than the equation would turn into  2 x 3+4 x 2-3 x 2- 6(3) which equals -10.

6 0
3 years ago
What is the median of this data set?<br> {29, 22, 23, 31, 29, 29, 22, 23}
Firlakuza [10]

Answer:

The median is 26

Step-by-step explanation:

A "median" is equivalent to when the terms are arranged in the proper order, whichever term is in the "middle".

So- first, arrange the terms in ascending order.

[22, 22, 23, 23, 29, 29, 29, 31]

There are an even number- eight- terms in total, so we will take the average of the two "middle" terms.

(29+23)/2; 29 and 23 are the "middle" terms, and there are two of them.

(52)/2 = 26

Therefore, the median is 26.

I hope this helped! :)

4 0
2 years ago
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Ivanshal [37]
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8 0
3 years ago
Select the TRUE statement
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7 0
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The nicotine content in cigarettes of a certain brand is known to be right-skewed with mean (in milligrams) μ and a known standa
RideAnS [48]

Answer:

There is enough evidence to support the claim the mean nicotine content is actually higher than advertised.          

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 1.5

Sample mean, \bar{x} = 1.53

Sample size, n = 100

Alpha, α = 0.05

Population standard deviation, σ = 0.17

First, we design the null and the alternate hypothesis

H_{0}: \mu = 1.5\\H_A: \mu > 1.5

We use one-tailed z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{1.53 - 1.5}{\frac{0.17}{\sqrt{100}} } = 1.7647

Now, we calculate the p-value from the standard normal table.

P-value = 0.038807

Since the p-value is less than the significance level we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Conclusion:

Thus, there is enough evidence to support the claim the mean nicotine content is actually higher than advertised.

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4 years ago
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