Use the image below to find the missing side lengths.
1 answer:
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Step-by-step explanation:
1. All the trigonometric values can be found using the unit circle. See attached table.
2. Graph:
desmos.com/calculator/10n7yrm3tm
3. All trig functions are periodic functions. The period of secant and cosecant is 2π. The period of cotangent is π.
4. Using the table from step 1 and the graph from step 2, secant has a domain of x ≠ pi/2, 3pi/2 and a range of x ≤ -1, x ≥ 1. Cotangent has a domain of x ≠ 0, pi, 2pi and a range of -∞ < x < ∞.
5. Graph:
desmos.com/calculator/tldiqt7qra
Cosecant has the same graph as secant shifted π/2 to the right. So they have different domains, but the same range.
Answer:
Step-by-step explanation:
You start noticing that for x = 9 g(x) =0, and for x= -7 the function isn't defined.
That splits the number lines in 3 areas: x<-7; -7<x<9, and x>9. (notice the strict inequalities since we already discussed the breaking points.
Let's try a point in each interval, namely, since i like the values, -10, 0, 10.
We have all the informations we need. The value we need are