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melisa1 [442]
3 years ago
10

Last winter, Anne was charged $838.35 for 9,315 KWh of electricity. What did her company charge per killowatt hour of electricit

y
Mathematics
1 answer:
DaniilM [7]3 years ago
6 0
To solve this do:

838.35/9315= 0.09.

This means the company charged $.09 for every kilowatt of electricity used.
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One Endpoint is 9,18 and the midpoint is 14,16 what the other end point
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\bf \textit{middle point of 2 points }\\ \quad \\
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&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ 9}}\quad ,&{{ 18}})\quad 
%  (c,d)
&({{ x}}\quad ,&{{ y}})
\end{array}\qquad
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\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)

\bf \left( \cfrac{x+9}{2}~,~\cfrac{y+18}{2} \right)=\stackrel{\textit{midpoint}}{(14,16)}\implies 
\begin{cases}
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\boxed{x=19}\\
-------\\
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3 years ago
What’s the answer to this
Ipatiy [6.2K]
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madreJ [45]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
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