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3 years ago

How many different ways can the letters of MOM be arranged

Mathematics

1 answer:

musickatia [10]3 years ago

5 0

I believe 3. MOM, MMO, and OMM

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Simplify the given exponential expression.

Andrews [41]

The rule for multiplying similar bases with exponents is:

(a^b)*(a^c)=a^(b+c)

In this case you have:

(x^9)(x^2)

x^(9+2)

x^11

6 0

3 years ago

Read 2 more answers

Which of the following relations are not functions? Select all that apply

alekssr [168]

A,b,c, d that’s the answer

5 0

3 years ago

Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.

NISA [10]

Answer:

$\frac{\sqrt{\pi}}{4}$

Step-by-step explanation:

You are going to integrate the following function:

$g(x)=x*f(x)=x*xe^{-x^2}=x^2e^{-x^2}$ (1)

furthermore, you know that:

$\int_0^{\infty}e^{-x^2}=\frac{\sqrt{\pi}}{2}$

lets call to this integral, the integral Io.

for a general form of I you have In:

$I_n=\int_0^{\infty}x^ne^{-ax^2}dx$

furthermore you use the fact that:

$I_n=-\frac{\partial I_{n-2}}{\partial a}$

by using this last expression in an iterative way you obtain the following:

$\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}}$ (2)

with n=2s a even number

for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:

$\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}$

5 0

3 years ago

Read 2 more answers

How do i solve this

laila [671]

The ratio is 2:3 for the side lengths of the triangles.

so 6:9 is one side and 5:x would be the other side

2/3 of five is 3.33 and multiplying that by 2 gives you 6.67

4 0

4 years ago

F(x) = -x^2<br> Find f(3)

Lemur [1.5K]

Answer:

Step-by-step explanation:

f(x) = -x^2

f(3) = -3^2

f(3) = 9

5 0

3 years ago