Let 
be the speed of train A, and let's set the origin in the initial position of train A. The equations of motion are
where 
are the positions of trains A and B respectively, and t is the time in hours.
The two trains meet if and only if 
, and we know that this happens after two hours, i.e. at 
Solving this equation for v we have
So, train A is travelling at 105 km/h. This implies that train B travels at
3(2x-4)=2(x+4)
6x-12=2x+8
6x-2x=8+12
4x=20
x=20/4
x=5
Answer:
6/7
Step-by-step explanation:
i am not sure if your question cut off but i am going to answer what i see on my side of the screen.
2/7 divided by 1/3 is the same as 2/7 times 3/1; since we multiply by the reciprocal when we divide fractions.
Therefore,
2/7 * 3/1 = 6/7
Answer:
Around 13 lunches
Step-by-step explanation:
If you divide 100 and 7.50, you get 13.33 and if you round it, it equals 13.
