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stealth61 [152]
3 years ago
6

Solve -6x+3-12x-8=31

Mathematics
2 answers:
Gwar [14]3 years ago
6 0
X = -2

Combine terms to get:

-18x - 5 = 31

Add 5 to both sides

-18x = 36

Divide by -18

x = -2
baherus [9]3 years ago
5 0

Answer: x=-6

Step-by-step explanation:

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Help me please I give brainliest and be serious than you
Naddik [55]

Answer:

15) <u><em>y= 1/2 + 3.75</em></u>

16) <u><em>y = x</em></u>

Step-by-step explanation:

For #15)

<em>Equation used: y=mx+b ; Slope: y₂ - y₁ / x₂ - x₁</em>

1) First, you need to pick any 2 points on the graph. I'll use (6,3) and (8,4).

2.1) Then you'll use the <em>slope </em>equation to find the slope (m) of your equation.

(y) ~ 4 - 3 = 1

(x) ~ 8 - 6 = 2

Slope= 1/2

3) So from the look of the answers, the y here is 3.75 so you can trust that.

4) The final equation is <u><em>y= 1/2 + 3.75</em></u>

<u><em /></u>

For #16)

Use the same steps as #15. You can still choose whatever points/plots you want. Ima use (5,4) and (6,5).

(y) ~ 4 - 3 = 1

(x) ~ 6 - 5 = 1

slope= 1 or x

Answer: y=x

<em>Your welcome for the answer! <3</em>

8 0
3 years ago
16. Which of the following are equivalent to(x) 16xA) g(r) 8.21B) g(c) 4096.16-3g (x) -4.4xD) g(x) 0.0625-16'+1E) g(x) 32.16E) g
swat32
F(x) = 16ˣ

A. g(x) = 8(2ˣ)
    g(x) = (2³)(2ˣ)
    g(x) = 2ˣ⁺³
The answer is not A.

B. g(x) = 4096(16ˣ⁻³)
    g(x) = (16³)(16ˣ⁻³)
    g(x) = 16ˣ
The answer is B.

C. g(x) = 4(4ˣ)
     g(x) = 4ˣ⁺¹
The answer is not C.

D. g(x) = 0.0625(16ˣ⁺¹)
     g(x) = (16⁻¹)(16ˣ⁺¹)
     g(x) = 16ˣ
The answer is D.

E. g(x) = 32(16ˣ⁻²)
    g(x) = (2⁵)(2⁴ˣ⁻⁸)
    g(x) = 2(⁴ˣ⁻³)
The answer is not E.

F. g(x) = 2(8ˣ)
    g(x) = 2(2³ˣ)
    g(x) = 2³ˣ⁺¹
The answer is not F.

The answer is B and D.
6 0
3 years ago
A child builds two wooden train sets. The path of one of the trains can be represented by the function y = 2cos2x, where y repre
Svet_ta [14]

Using a trigonometric equation, it is found that it will take 2.28 minutes until the two trains are first equidistant from the child.

<h3>What is the distance of each train to the child?</h3>

The distance of the first train is:

y_1 = 2\cos^{2}x

The distance of the second train is:

y_2 = 3 + \cos{x}

<h3>When are the trains equidistant to the child?</h3>

When y_1 = y_2, hence:

2\cos^{2}x = 3 + \cos{x}

The following substitution is made:

z = \cos{x}

Hence:

2z^2 = 3 + z

2z^2 - z - 3 = 0

Which is a quadratic equation with coefficients a = 2, b = -1, c = -3, hence:

\Delta = b^2 - 4ac = (-1)^2 - 4(1)(-3) = 13

z_1 = \frac{-b + \sqrt{\Delta}}{2a} = \frac{1 + \sqrt{13}}{4} = 1.5

z_2 = \frac{-b - \sqrt{\Delta}}{2a} = \frac{1 - \sqrt{13}}{4} = -0.65

Then, applying the trigonometric equation, considering that -1 \leq z \leq 1 due to the range of the cosine function:

z_2 = \cos{x_2}

x_2 = \arccos{z_2} = \arccos{-0.65} = 2.28

It will take 2.28 minutes until the two trains are first equidistant from the child.

You can learn more about trigonometric equations at brainly.com/question/2088730

8 0
3 years ago
The volume of a cylinder is 4nx cubic units and its height is x units.
svetlana [45]

Answer:

6nx + 7p – 14p + 2nx – 6x

= 8nx -7p = 6x

answer is A.

8nx – 7p – 6x

Step-by-step explanation:

4 0
3 years ago
The screening process for detecting a rare disease is not perfect. Researchers have developed a blood test that is considered fa
lesya692 [45]

Answer:

Type I: 1.9%, Type II: 1.6%

Step-by-step explanation:

given null hypothesis

H0=the individual has not taken steroids.

type 1 error-falsely rejecting the null hypothesis

⇒   actually the null hypothesis is true⇒the individual has not taken steroids.

 but we rejected it ⇒our prediction is the individual has taken steroids.

typr II error- not rejecting null hypothesis when it has to be rejected

⇒actually null hypothesis is false ⇒the individual has taken steroids.

but we didnt reject⇒the individual has not taken steroids.

let us denote

the individual has taken steroids by 1

the individual has not  taken steroids.by 0

                            predicted

                              1       0

   actual          1    98.4%  1.6%

                        0   1.9%   98.1%

so for type 1 error  

 actual-0

predicted-1

therefore from above table we can see that probability of Type I error is 1.9%=0.019

so for type II error

   actual-1

predicted-0

therefore from above table we can see that probability of Type I error is 1.6%=0.016

5 0
3 years ago
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