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sergejj [24]
3 years ago
13

I can get everything else but this one stumps me

Mathematics
1 answer:
navik [9.2K]3 years ago
3 0
What do you solve for ?
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3 years ago
PLEASE HELP ME WITH THIS PROBLEM!!!
Elanso [62]

Due to gravity, as the food flies across to room, it follows the path of a

parabola.

  • Harold is approximately <u>4.018 feet tall</u>

Reasons:

The path followed by the food (the projectile) is a parabola

The vertex form of the equation of a projectile is; y = a·(x - h)² + k

Where;

(h, k) = The vertex

The horizontal coordinates of the vertex = Half the range

Therefore;

For Jamal, (h, k) = (11, 8)

At x = 0, y = 0, therefore;

0 = a·(0 - 11)² + 8

-121·a = 8

\displaystyle a = \mathbf{-\frac{8}{121}}

Which gives;

\displaystyle The \ path \ of \ Jamal's  \ food \ is, \ y = \mathbf{-\frac{8}{121} \cdot (x - 11)^2 + 8}

For Dinah, we have;

y = a·(x - h)² + k

(h, k) = (13, 5)

At x = 0, y = 0, therefore;

0 = a·(0 - 13)² + 5

-169·a = 5

\displaystyle a = -\frac{5}{169}

Which gives;

\displaystyle The \ path \ of \ Dinah's \ food \ is, \ y = \mathbf{ -\frac{5}{169} \cdot (x - 13)^2 + 5}

At Harold's height, we have that the elevation of both food projectile are equal, therefore;

Height of Jamal's food projectile = Height of Dinah's food projectile

Which gives;

\displaystyle  -\frac{8}{121} \cdot (x - 11)^2 + 8 = \mathbf{-\frac{5}{169} \cdot (x - 13)^2 + 5}

\displaystyle   \frac{8}{121} \cdot (x - 11)^2-\frac{5}{169} \cdot (x - 13)^2 + 5 - 8 = 0

\displaystyle \frac{747}{20449} \cdot x^2 - \frac{98}{143} \cdot x -\frac{1}{99009900990} = 0

\displaystyle \frac{747}{20449} \cdot x^2 \approx \frac{98}{143} \cdot x

\displaystyle \frac{747}{20449} \cdot x \approx \frac{98}{143}

\displaystyle  x \approx \frac{98}{143} \times \frac{20449}{747} \approx 18.76

x ≈ 18.76

Therefore, at Harold's height, the horizontal distance from where the food flies, x ≈ 18.76 feet.

Therefore, Harold's height is given by plugging in <em>x </em>≈ 18.76 feet in either of the projectile motion as follows;

\displaystyle Harold's \ height \ h \approx  -\frac{8}{121} \cdot (18.76 - 11)^2 + 8 \approx \mathbf{4.018}

Harold height is approximately <u>4.018 feet</u>.

Learn more about projectile motion here:

brainly.com/question/11049671

6 0
3 years ago
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