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Contact [7]
2 years ago
7

-3m+10=25 need this fast please!

Mathematics
1 answer:
Ymorist [56]2 years ago
7 0

Answer:

m=-5

Step-by-step explanation:

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The diameter of a circle is 8 meters. What is the circle's circumference?
k0ka [10]

Answer:

25.13 square meters

Step-by-step explanation:

The formula for finding the circumference of a circle is πd or pi times the diameter

Diameter = 8 meters

Pi = 3.14

3.14 times 8 = 25.13

4 0
3 years ago
3≤7+g<br><br> Help <br><br><br> I’m famous
oee [108]

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

Let's solve your inequality step-by-step.

3 ≤ 7 + g

Step 1:Simplify both sides of the inequality.

3 ≤ g + 7

Step 2: Flip the equation.

g + 7 ≥ 3

Step 3: Subtract 7 from both sides.

g + 7 − 7 ≥ 3 − 7

g ≥ −4

Answer:

g ≥ −4

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

8 0
2 years ago
Read 2 more answers
3)June 2019-In the diagram below of AABC, D is a
Alexeev081 [22]

Answer:

BC = 23.8

Step-by-step explanation:

See the diagram attached.

Given AC ║ DE and BD = 5, DA = 12 and BE = 7.

We have to find BC.

Since, AC ║ DE, so, Δ ABC and Δ DBE are similar.

If two triangles are similar then the ratio of their corresponding sides remains the same.

Hence, \frac{BD}{BA} = \frac{BE}{BC}

⇒ \frac{5}{12 + 5} = \frac{7}{BC}

⇒ BC = \frac{7 \times 17}{5} = 23.8 (Answer)

7 0
3 years ago
Find the sequence 3n-1
aivan3 [116]

a(1) = 3(1)-1 = 3-1 = 2

a(2) = 3(2)-1 = 6-1 = 5

a(3) = 3(3)-1 = 9-1 = 8

So, the sequence would be 2,5,8,11....

6 0
3 years ago
Please help me thank you
Hoochie [10]

Answer:

\large\boxed{\sin2\theta=\dfrac{\sqrt3}{2},\ \cos2\theta=\dfrac{1}{2}}

Step-by-step explanation:

We know:

\sin2\theta=2\sin\theta\cos\theta\\\\\cos2\theta=\cos^2\theta-\sin^2\thet

We have

\sin\theta=\dfrac{1}{2}

Use \sin^2\theta+\cos^2\theta=1

\left(\dfrac{1}{2}\right)^2+\cos^2\theta=1\\\\\dfrac{1}{4}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{1}{4}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{4}{4}-\dfrac{1}{4}\\\\\cos^2\theta=\dfrac{3}{4}\to\cos\theta=\pm\sqrt{\dfrac{3}{4}}\to\cos\theta=\pm\dfrac{\sqrt3}{\sqrt4}\to\cos\theta=\pm\dfrac{\sqrt3}{2}\\\\\theta\in[0^o,\ 90^o],\ \text{therefore all functions have positive values or equal 0.}\\\\\cos\theta=\dfrac{\sqrt3}{2}

\sin2\theta=2\left(\dfrac{1}{2}\right)\left(\dfrac{\sqrt3}{2}\right)=\dfrac{\sqrt3}{2}\\\\\cos2\theta=\left(\dfrac{\sqrt3}{2}\right)^2-\left(\dfrac{1}{2}\right)^2=\dfrac{3}{4}-\dfrac{1}{4}=\dfrac{3-1}{4}=\dfrac{2}{4}=\dfrac{1}{2}

3 0
3 years ago
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