Answer:
≈ 0.52
Step-by-step explanation:
P( head ) = 2/3 , P( tail ) = 1/3
when a head is tossed ; Gambler A wins $1
when a tail is tossed : Gambler B wins $1
<u>Determine the P( Gambler A wins the game ) if he starts with I dollars</u>
Assuming I = $1
n = 5
p ( head ) = P( winning ) = 0.66
p( losing ) = 0.33
applying the conditional probability in Markov which is ;
Pₓ = pPₓ₊₁ + (1 - p) Pₓ₋₁
P( 1) = 0.66P₂ + 0.33P₀
resolving the above using with Markov probability
P( 1 ) = 0.51613
hence the probability of Gambler A winning the game if he starts with $1
≈ 0.52
105% <span>Just move the decimal to the right 2 places or multiply times 100, same thing</span>
1 nickel = 5 cents
1 dime = 10 cents
13 nickels = 13 *5 = 65 cents
6 dimes = 6*10 = 60 cents.
Total = 65 + 60 = 125 cents.
= 125 cents or $1.25
Answer:
Step-by-step explanation:
V≈24543.69
Answer:
0.194
Step-by-step explanation:
Probability that BOTH are democrats means probability of <u>"one being democrat"</u> AND <u>"another also being democrat"</u>.
The AND means we need to MULTIPLY the individual probability of a person being democrat.
Probability that a voter is democrat is 44% (0.44) -- stated in the problem
Now, Probability BOTH being Democrats is simply MULTIPLYING 0.44 with 0.44
Rounded to nearest thousandth, 0.194
Last answer choice is correct.
