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elena55 [62]
3 years ago
6

Angle measure for 225

Mathematics
1 answer:
Alex73 [517]3 years ago
4 0

Answer:

3.92699 radians

Step-by-step explanation:

the formula fro converting degrees into radians is quite simple as it is the following: 225° × π/180 = 3.927rad

if π=3.14 and 180=1/2 of a circle. than 3.92699 would be the answer

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yaroslaw [1]

Answer:

n= 11 & n = 13 is the answer

8 0
3 years ago
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How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the
miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

<h3>8d.</h3>

\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}

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<h3>9b.</h3>

\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}

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<h3>10b.</h3>

\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}

Neither solution makes any denominator be zero, so both are good solutions.

8 0
3 years ago
Suppose that c varies jointly with d and the square of g, and c = 30 when d = 15 and g = 2.
maksim [4K]

Answer:

d = \dfrac{3}{16}

Step-by-step explanation:

c varies jointly with d and the square of g

c\propto dg^2

c=kdg^2

where, k is constant of proportionality.

Put the given value c = 30 when d = 15 and g = 2 and find out k

30=k\cdot 15\cdot 2^2

k=\dfrac{1}{2}

c=\dfrac{1}{2}kg^2

If c = 6 and g = 8 then d = ?

6=\dfrac{1}{2}\cdot d\cdot 8^2

d=\dfrac{6\cdot 2}{8^2}

d=\dfrac{3}{16}

Hence, The value of d is \dfrac{3}{16}

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Solve for x.<br> X -8 = -11<br><br> With step by step explanation or with ur work.
igor_vitrenko [27]

<em><u>To </u></em><em><u>find:</u></em>

<em><u>=</u></em><em><u>></u></em><em><u> </u></em><em><u>The</u></em><em><u> </u></em><em><u>value</u></em><em><u> of</u></em><em><u> </u></em><em><u>x</u></em>

<em><u>=</u></em><em><u>></u></em>

<em><u>x - 8 =  - 11</u></em>

<em><u>Now,</u></em><em><u> we'll</u></em><em><u> </u></em><em><u>move </u></em><em><u>-</u></em><em><u>8</u></em><em><u> </u></em><em><u>to </u></em><em><u>the</u></em><em><u> </u></em><em><u>other</u></em><em><u> </u></em><em><u>side </u></em><em><u>i.e </u></em><em><u>the </u></em><em><u>RHS </u></em><em><u>side,</u></em>

<em><u>which</u></em><em><u> </u></em><em><u>results</u></em><em><u> </u></em><em><u>in </u></em><em><u>the </u></em><em><u>change</u></em><em><u> </u></em><em><u>of </u></em><em><u>it's</u></em><em><u> </u></em><em><u>sign(</u></em><em><u>-</u></em><em><u> </u></em><em><u>converts</u></em><em><u> </u></em><em><u>into </u></em><em><u>+</u></em><em><u>)</u></em>

<em><u>=</u></em><em><u>></u></em>

<em><u>x =  - 11 + 8</u></em>

<em><u>Now </u></em><em><u>,</u></em><em><u> we'll</u></em><em><u> </u></em><em><u>add </u></em><em><u>the </u></em><em><u>Numbers</u></em>

<em><u>=</u></em><em><u>></u></em>

<em><u>x =   - 3</u></em>

<h2><em><u>Hence</u></em><em><u>,</u></em><em><u>-</u></em><em><u>3</u></em><em><u> </u></em><em><u>is </u></em><em><u>the</u></em><em><u> </u></em><em><u>required</u></em><em><u> </u></em><em><u>answer</u></em><em><u>.</u></em></h2>

<em><u>^</u></em><em><u>-</u></em><em><u>^</u></em>

8 0
3 years ago
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If A=N , B=W then A-B is : *<br>{ }<br>N<br>W<br>None​
german
I’m going with none because it would just be N-W= blank. Is the blank n or w. I mean it could be one of those but I don’t think you know enough about the question for it to be N or W. So I would say none. Sorry if I’m wrong.
8 0
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