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ruslelena [56]
3 years ago
13

Please help will give brainliest i need this its due wednesday and there are like 45-50 questions

Mathematics
2 answers:
creativ13 [48]3 years ago
8 0

Answer:

i think its a

Step-by-step explanation:

sorry if im wrong just stressd out. good luck.

Jet001 [13]3 years ago
7 0

Answer:

The anwser is a

Step-by-step explanation:

Because on the red point it 24

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I will mark you as brainliest if you get the question right
Ann [662]

Answer:

103

Step-by-step explanation:

x = 180-77 = 103

because it's a straight line, so 180 - 77 to find x

4 0
2 years ago
if a ball is rolling down hill and accelerating at a rate of 2m/s^2 because of a 2N net force. What is the mass of the ball?
Vedmedyk [2.9K]

Answer:

<h3>1kg</h3>

Step-by-step explanation:

According to Newton's second law

Force = mass * acceleration

Given

Force = 2N

acceleration = 2m/s^2

Mass =Force/Acceleration

Mass = 2/2

Mass =1kg

Hence the mass of the ball is 1kg

8 0
2 years ago
3/4(-10+2/5) please answer asap
Tju [1.3M]

Answer:

3/4(-10+2+2/5)

answer -5.7

Step-by-step explanation:

-

5 0
2 years ago
Mrs. johnson's and mr. wei's classes are participating in the Meridian School arts and crafts exhibit. Their spaces will be next
Nat2105 [25]

Answer:

See explanation

Step-by-step explanation:

Ms. Johnson space has 48 carpet squares.

Mr. Wei space has 36 carpet squares.

Factorize these two numbers:

48=2\cdot 2\cdot 2\cdot 2\cdot 3\\ \\36=2\cdot 2\cdot 3\cdot 3

All common factors are 1, 2, 3, 4, 6, 12

<u>All possibilities:</u>

1. If Ms. Johnson space width and Mr. Wei space width is 1 carpet, then Ms. Johnson space length is 48 carpets and Mr. Wei space length is 36 carpets.

2. If Ms. Johnson space width and Mr. Wei space width is 2 carpets, then Ms. Johnson space length is 24 carpets and Mr. Wei space length is 18 carpets.

3. If Ms. Johnson space width and Mr. Wei space width is 3 carpets, then Ms. Johnson space length is 16 carpets and Mr. Wei space length is 12 carpets.

4. If Ms. Johnson space width and Mr. Wei space width is 4 carpets, then Ms. Johnson space length is 12 carpets and Mr. Wei space length is 9 carpets.

5. If Ms. Johnson space width and Mr. Wei space width is 6 carpets, then Ms. Johnson space length is 8 carpets and Mr. Wei space length is 6 carpets.

6. If Ms. Johnson space width and Mr. Wei space width is 12 carpets, then Ms. Johnson space length is 4 carpets and Mr. Wei space length is 3 carpets.

4 0
3 years ago
Read 2 more answers
student tickets for the football game cost $12 each and adult ticket cost $20 $1,720 was collected for the 120 ticket sold at la
erik [133]

Answer:

85 student tickets and 35 adult tickets were sold.

Step-by-step explanation:

Howdy!

We know that student tickets cost $12, adult ticket cost $20 and 120 tickets were sold.

So:

$12×A + $20×B = $1,720. Where A and B are the number of student tickets and adult tickets sold, respectively.

Given that 120 tickets were sold in total, we have that:

A + B = 120

So the system of equations to be solved is the following:

$12×A + $20×B = $1,720                    (1)

A + B = 120                                          (2)

Solving for 'A' in equation (2) we get:

A = 120 - B

Substituting this value into equation (1) we get:

$12×(120 - B) + $20×B = $1,720

Solving for 'B' we have:

$12×(120 - B) + $20×B = $1,720

$1,440 - $12×B + $20×B = $1,720

$1,440 + $8×B = $1,720

$8×B = $1,720 - $1,440

$8×B = $280

B = 35 tickets.

Given that B = 35, then A = 120 - 35 = 85 tickets.

So 85 student tickets and 35 adult tickets were sold.

4 0
3 years ago
Read 2 more answers
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