Answer:
There are asymptotes at x = three-halves and x = negative one-third.
Step-by-step explanation:
f(x) = (x + 1)/ (6x^2 - 7x - 3)
= (x + 1)( / (6x^2 + 2x - 9x - 3)
= (x + 1) / (2x(3x + 1) - 3(3x + 1))
= (x + 1) / (2x - 3)(3x + 1)
Now x = 3/2 and x = -1/3 both make te denominator zero so these are both asymptotes.
108 / 1376 is the probability that a student participates in both sports and music.
<u>Step-by-step explanation:</u>
It is given that,
A suburban high school has a population of 1376 students.
- Let the event A be the no.of students participated in sports.
- Let the event B be the no.of students participated in music.
The number of students who participate in sports is 649.
The number of students who participate in music is 433.
<u>To find the probability of event A (sports) :</u>
P(sports) = No.of students participated in sports / Total students.
⇒ 649 / 1376
∴ P(A) = 649 / 1376
<u>To find the probability of event B (music) :</u>
P(music) = No.of students participated in music / Total students.
⇒ 433 / 1376
∴ P(B) = 443 / 1376
From the question, we know that the probability that a student participates in either sports or music is 974 /1376.
∴ P(A∪B) = 974 / 1376
<u>To find the probability that a student participates in both sports and music :</u>
The formula used here is,
P(A∩B) = P(A) + P(B) - P(A∪B)
⇒ 649 / 1376 + 433 / 1376 - 974 /1376
⇒ 108 / 1376
∴ P(A∩B) = 108 / 1376
2x-2y
I couldn’t tell if the first figure was a one or a L or i so I solved it as a 1
Answer:
i believe the answer to this is a total of 300 people because you multiply the ten percent into the 30 people which factors out some numerical values, so then your answer as i just said is 300 people in total attended the game.
Step-by-step explanation:
17/8 -11/3
51/24-88/24
-37/24 simplified is -1 13/24
