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yulyashka [42]
3 years ago
10

Simplify: ly - 2x - 3y + 4x

Mathematics
2 answers:
Anettt [7]3 years ago
6 0

Answer:

ly + 2 x − 3y

vitfil [10]3 years ago
3 0
2x-2y
I couldn’t tell if the first figure was a one or a L or i so I solved it as a 1
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Mikayla is training for a half-marathon. At the beginning of her training, she is able to run 2 miles without stopping. Her goal
ivanzaharov [21]

Alright, lets get started.

At the beginning of her training, she is able to run 2 miles without stopping means 2 will be in the addition when we will write the equation for her running miles.

Her goal is to increase her distance by three quarters of a mile each week.

Means in first week, she will add the distance = \frac{3}{4} miles

Suppose she runs x weeks, so shee will add distance = \frac{3}{4}x

So, suppose she runs total number of miles = d, then

d = 2 + \frac{3}{4}x

Where d is total numer of miles she runs

x is number of weeks    :   Answer

Hope it will help :)


5 0
3 years ago
I need help! I'm running out of coins!!!​
Law Incorporation [45]

Answer:

4) m∠F ≈ 67°

5) m∠x ≈ 53°

6) m∠? ≈ 16°

Step-by-step explanation:

(It's not letting me post, so I'll attach screenshots:)

8 0
3 years ago
CD is the perpendicular bisector of AE. If AC=4x and BC=6x-10, whats is the calue of x?
alekssr [168]
You use the Pitagora formula:

CD^2+BD^2= (6x-10)^2
CD^2+AD^2=16x^2

AD^2-BD^2=16x^2-(36x^2-120x+100)
0=-20x^2+120x-100
x^2-6x+5=0
x^2-x-5x+5=0
x(x-1)-5(x-1)=0
(x-1)(x-5)=0
x1=1 but if x=1 it means that BC=-4 which cannot be possible
x2=5 so x=5

The answer to your question is C. I hope that this is the answer that you were looking for and it has helped you.
4 0
3 years ago
Read 2 more answers
For f(x) = 2x-1 and g(x)= x+3, find f(g(x))
Over [174]

Answer:

C

Step-by-step explanation:

Plug in g(x) into the variable x of f(x), we get:

(fog) = 2(x+3)-1 = 2x+6-1=2x+5

7 0
3 years ago
Graph the linear inequality.<br> y&lt;2
Leya [2.2K]

Answer:

See attachment.

Step-by-step explanation:

We want to graph the linear inequality y<2

We  first of all graph  the corresponding linear equation y=2 with a dashed line because all points on this line do not satisfy the inequality.

We then shade below the line y=2, to show that all points below the boundary line are solution to the inequality y<2

7 0
3 years ago
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