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ipn [44]
3 years ago
12

A bake sale committee wants to raise $174 for a donation to a local charity. They set aside $12 of their profit at the end of ea

ch day. How many days will it take them to raise enough money for the whole donation?
Mathematics
1 answer:
Flauer [41]3 years ago
8 0

It will take 14.5 days or 15 days (rounded off)

Step-by-step explanation:

  • Step 1: Given that the total money to be raised = $174. Money set aside of their profit = $12. Find number of days taken to raise this money

Number of days that will be taken = 174/12 = 14.5

∴ It will take 15 days (rounded off)

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Please help 100 points
emmainna [20.7K]

Answer:

Choices A, C, E

Step-by-step explanation:

The prices are proportional, so divide any price by the corresponding number of pounds to find the unit cost.

$1.47/(3 lb) = $0.49/lb

The unit cost is $0.49 per lb.

Now we look in the choices to see which choice has a unit price of $0.49/lb.

We divide each price by its number of pounds to fund each unit cost. Every choice with a unit cost of $0.49/lb is an answer.

A $0.98/(2 lb) = $0.49/lb     Choice A works

B $4.45/(7 lb) = $0.64/lb      Choice B does not work

C $2.94/(6 lb) = $0.49/lb     Choice C works

D $0.54/(1 lb) = $0.54/lb     Choice D does not work

E $3.92/(8 lb) = $0.49/lb     Choice E works

Answer: Choices A, C, E

6 0
3 years ago
A population of values has a normal distribution with μ = 157.7 and σ = 57 . You intend to draw a random sample of size n = 24 .
alexgriva [62]

Answer:

z=1.64

And if we solve for a we got

a=157.7 +1.64*57=251.18

So the value of height that separates the bottom 95% of data from the top 5% is 251.18.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(157.7,57)  

Where \mu=157.7 and \sigma=57

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.05   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64. On this case P(Z<1.64)=0.95 and P(z>1.64)=0.05

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.64

And if we solve for a we got

a=157.7 +1.64*57=251.18

So the value of height that separates the bottom 95% of data from the top 5% is 251.18.  

5 0
3 years ago
Leah had $24. She bought 7 sharpies and was left with $10. How much did each sharpie cost?
lions [1.4K]

Answer: 2$ per sharpie

Step-by-step explanation:24 - 10= 14     7 x 2 =14

3 0
3 years ago
Suppose that water is pouring into a swimming pool in the shape of a right circular cylinder at a constant rate of 3 cubic feet
gtnhenbr [62]

Answer:

Therefore the height of the water in the pool changes at the rate of \frac{1}{3\pi} feet per minute.

Step-by-step explanation:

Given that  the shape of swimming pool is right circular cylinder.

The  rate of water pouring in the pool = 3 cubic feet per minute.

It means the rate of change of volume is 3 cubic feet per minute.

\frac{dv}{dt}=3 cubic feet per minute.

When the volume of the swimming pool changed it means the height of the water level of the pool change and the radius of the swimming pool remains constant.

Let the height of the pool be h.

The volume of the pool is = \pi 3^2 h  cubic feet

                                          =9\pi h cubic feet

Therefore,

v =9\pi h

Differentiating with respect to t

\frac{dv}{dt}= 9\pi \frac{dh}{dt}

Putting \frac{dv}{dt}=3

3=9\pi \frac{dh}{dt}

\Rightarrow \frac{dh}{dt} =\frac{3}{9\pi}

\Rightarrow \frac{dh}{dt} =\frac{1}{3\pi}

The change of height of the pool does not depend on the depth of the pool.

Therefore the rate of change of height of the water in the pool is \frac{1}{3\pi} feet per minute.

6 0
2 years ago
1. Juan paid $2.52 for 12 ounces of peanuts
Alborosie

Answer:

$0.21

Step-by-step explanation:

2.52/12

6 0
3 years ago
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