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Feliz [49]
3 years ago
7

Plzzzz help!!!!!!!!!!!!!

Mathematics
2 answers:
sertanlavr [38]3 years ago
7 0
The answer to the question I believe is C
dusya [7]3 years ago
7 0
The answer is C i think
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How to use original price and markup to find retail price? Original price is $62 and %15 mark up.. What's the retail price?
Sonbull [250]

Answer:

pretty sure its $72.94

Step-by-step explanation:

6 0
3 years ago
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You mix 1/2 cup of red paint for every 1/4 cup of blue paint to make 12 cups of
Serhud [2]
4 cups of blue paint and 8 cups of red paint

explanation

to pour one cup of blue paint, two cups of red paint has to be poured.
since when you add both those it adds to 3
so multiply each by 4 to get 4 cups of blue paint and 8 cups of red paint
3 0
2 years ago
The population of the town was 25,000 people.Then 3,200 people moved away.What was the percent of increase?
german

Answer:

-12.8%

Step-by-step explanation:

To calculate the percent decrease, we:

  1. Find the difference between the new value and the original
  2. Divide the number by the original
  3. Multiply by 100 and the % symbol.

The population of the town originally had 25,000. 3,200 people moved away. This means that the new population is 21,800.

  1. 21,800-25,000=-3,200
  2. -3,200/25,000=-0.128
  3. -0.128(100)=-12.8%

The towns population decreased by 12.8%.

6 0
3 years ago
You have two fair, six-sides dice. However, the dice have been modified so that instead or 1,2,3,4,5,6 the sides are numbered 1,
Tamiku [17]

Answer:

30.56%

Step-by-step explanation:

Let the sides on each dice be labeled as 1, 2a, 2b, 2c, 3, 4.

The sample space for the sum of the values being 4 is:

S={1,3; 3,1; 2a,2a; 2a,2b; 2a,2c; 2b,2a; 2b,2b; 2b,2c; 2c,2a; 2c,2b; 2c,2c}

There are 11 possible sums out of the 36 possible outcomes that result in a sum of 4. Therefore, the probability their total is 4 is:

P(S) =\frac{11}{36}=0.3056 =30.56\%

There is a 30.56% probability that their sum is 4.

6 0
3 years ago
Is the mathematical limit you've been studying in any way connected to a common speed limit? Are the limits you've calculated an
Alenkinab [10]

Answer:

Please see attachment

Step-by-step explanation:

Please see attachment

6 0
3 years ago
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