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3 years ago

What are the next 2 numbers in the pattern 1, 4, 9, 16, 25, 36, 49, . . .

2 answers:

5 0

The next two numbers would be 64 and 82

1+3=4
4+5=9
9+7=16
16+9=25
25+11=36
36+13=49
Hope that you see the pattern here

GREYUIT [131]3 years ago

4 0

This pattern is adding the next odd number, starting with 3. For example, we can use the first few numbers:
1 + 3 = 4
4 + 5 = 9
9 + 7 = 16

This means that when we reach 49, we have to add 17 into it to get the answer of 66.

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which shows one way to determine the factors of 12x^3 - 2x^2 + 18x - 3 by grouping? A) 2x^2(6x - 1) + 3(6x - 1) B) 2x^2(6x - 1)

Eva8 [605]

Answer:

$2x^2(6x - 1) + 3(6x - 1)$

Step-by-step explanation:

Given

$12x^3 - 2x^2 + 18x - 3$

Required

Factorize

To start with; we need to group the expression into two

$(12x^3 - 2x^2) + (18x - 3)$

Factorize each grouped expression, using their common factor

$2x^2(6x - 1) + 3(6x - 1)$

From the list of given options;

Option A is correct

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3 years ago

Help! I have looked at so many lessons on writing exponential functions from a graph and nothing has helped.

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Answer:

y = $8(-\frac{1}{2})^x$

Step-by-step explanation:

Let the equation of the exponential function is,

y = a(b)ˣ

Since the graph of this function passes through two points $(4, \frac{1}{2})$ and (3, -1)

For the point $(4, \frac{1}{2})$ ,

$\frac{1}{2}=a(b)^4$ ---------(1)

For second point (3, -1),

-1 = a(b)³ ---------(2)

Divide equation (2) by equation (1),

$\frac{\frac{1}{2}}{-1}$ = $\frac{a(b)^4}{a(b)^3}$

$-\frac{1}{2}=b^{(4-3)}$

$-\frac{1}{2}=b$

From equation (2)

-1 = $a(-\frac{1}{2})^3$

-1 = $-\frac{1}{8}a$

a = 8

Therefore, equation of the exponential function will be,

y = $8(-\frac{1}{2})^x$

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3 years ago

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3 years ago

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Effectus [21]

Answer:

x=21.

Step-by-step explanation:

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