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gizmo_the_mogwai [7]

3 years ago

8

Factor completely 25−80+64

1 answer:

postnew [5]3 years ago

4 0

Answer:

9

Step-by-step explanation:

25-80=-55

-55+64=9

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Which is the rationalized form of the expression. A, B , C, or D?

grin007 [14]

Answer:

C

Step-by-step explanation:

Multiply the top and bottom, both by sqrtx-sqrt5. This is in order to rationalize the denominators.

You get answer C.

3 0

3 years ago

Bruce pitches for his little brother's baseball team. He has observed that the number of pitches a batter hits varies and is giv

liberstina [14]

Hello!

If Bruce observes that the number of pitches a batter hits varies and is given by the function f(x)=x-11, and the batters get {4, 12, 14, 27, 42}, then Bruce threw {15, 23, 25, 38, 53} pitches. We get this solution set by adding 11 to each element in the set {4, 12, 14, 27, 42}.
Have a nice day

6 0

3 years ago

B) Find the values of b.<br> b2 = 256<br> b =

Svetach [21]

B=16,-16................

5 0

3 years ago

Read 2 more answers

If lim x-> infinity ((x^2)/(x+1)-ax-b)=0 find the value of a and b

MAXImum [283]

We have

$\dfrac{x^2}{x+1}=\dfrac{(x+1)^2-2(x+1)+1}{x+1}=(x+1)-2+\dfrac1{x+1}=x-1+\dfrac1{x+1}$

So

$\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-ax-b\right)=\lim_{x\to\infty}\left(x-1+\frac1{x+1}-ax-b\right)=0$

The rational term vanishes as <em>x</em> gets arbitrarily large, so we can ignore that term, leaving us with

$\displaystyle\lim_{x\to\infty}\left((1-a)x-(1+b)\right)=0$

and this happens if <em>a</em> = 1 and <em>b</em> = -1.

To confirm, we have

$\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-x+1\right)=\lim_{x\to\infty}\frac{x^2-(x-1)(x+1)}{x+1}=\lim_{x\to\infty}\frac1{x+1}=0$

as required.

3 0

3 years ago

Is it A) , B) , C), D) , E)

Mrac [35]

Answer:

Part A) The statement is True

Part B) The statement is False

Part C) The statement is True

Part D) The statement is True

part E) The statement is False

Step-by-step explanation:

Part A) we have

$1.66..=1 \frac{6}{9}$

The statement Is True

Convert the repeating decimal 1.66.. to an equivalent fraction

Let

$x=1.66..\\ 10x=16.66..\\ 10x-x=16.66..-1.66..\\ 9x=15\\ x=15/9$

Convert to mixed number

$15/9=9/9+6/9=1 \frac{6}{9}$

therefore

$1.66..=1 \frac{6}{9}$

Part B) we have

$0.6 < 6\%$

The statement is false

Because

$6\%=6/100=0.06$

so

substitute

$0.6 < 0.06$ -----> is not true

Part C) we have

$45\% \leq4.5$

The statement is True

Because

$45\%=45/100=0.45$

substitute

$0.45 \leq4.5$ ----> is true

Part D) we have

$5^{2} \geq 16$

The statement is True

Because

$5^{2}=25$

substitute

$25 \geq 16$ ----> is true

Part E) we have

$9.25 > 9\frac{3}{4}$

The statement is false

Because

Convert mixed number to an improper fraction

$9\frac{3}{4}=\frac{9*4+3}{4}=\frac{39}{4}$

Convert decimal number to an improper fraction

$9.25=9\frac{1}{4}=\frac{9*4+1}{4}=\frac{37}{4}$

substitute

$\frac{37}{4} > \frac{39}{4}$ -----> is not true

8 0

3 years ago