We have a work problem right here. We can use knowledge on ration and proportion to answer this type of problem. We do as follows:
1 job / 2 hours + 1 job / 3 hours = 1 job / time it takes for both when working together
time it takes for both when working together = 1.2 hours
Answer:
W₂ is three times W₁ (W₂ = 3W₁)
Step-by-step explanation:
Applying,
W = ke²/2............. Equation 1
Where W = workdone in stretching the spring, k = spring constant, e = extension.
For W₁,
W₁ = ke₁²/2
Given: e₁ = 30-20 = 10 cm = 0.1 m
Substitute these value into equation 1
W₁ = k(0.1²)/2
W₁ = 0.005k Joules
For W₂,
W₂ = (ke/2)-W₁
Given: e = (40-20) = 20 cm = 0.1 m
Substitute these value into equation 1
W₂ = (k×0.2²/2)-0.005
W₂ = 0.015k Joules.
W₂/W₁ = 0.015k/0.005k
W₂/W₁ = 3
Therefore,
W₂ = 3W₁
<h3>Write the sum of the numbers as the product of their GCF and another sum</h3>
Answer 23: 56 + 64 = 8 (7 + 8)
Answer 24: 48 + 14 = 2 (24 + 7)
Answer 25: 30 + 54 = 6 (5 + 9)
Answer 26: 24 + 40 = 8 (3 + 5)
Answer 27: 55 + 66 = 11 (5 + 6)
Answer 28: 49 + 63 = 7 (7 + 9)
Answer 29: 40 + 25 = 5 (8 + 5)
Answer 30: 63 + 15 = 3 (21 + 5)
It seems that you have missed the most important detail for us to answer this question which is the table where we can base the values. I would be very much interested to help of you are going to attach it here. Let me know if you need more help next time. Have a great day!
Answer:
ello
Step-by-step explanation:
how are you
<h2>I hope you're fine</h2>
