Add: (3x2 - 5x + 6) + (9 - 8x - 4x2) A) 12x2 - 13x + 2 B) 7x2 + 3x - 3 C) 7x2 - 13x + 15 D) -x2 - 13x + 15

Mathematics

1 answer:

kati45 [8]2 years ago

4 0

Answer:

Step-by-step explanation:

So we have the expression:

$(3x^2-5x+6)+(9-8x-4x^2)$

Combine like terms:

$=(3x^2-4x^2)+(-5x-8x)+(6+9)$

Add or subtract:

$=(-1x^2)+(-13x)+(15)$

Simplify:

$=-x^2-13x+15$

Our answer is D

You might be interested in

4) 16 + 7 + 9 = 7 + 9 + 16 *

nlexa [21]

Answer:

a.) Commutative Property of addition

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

3 Express the following fractions in a different way:<br>(a) 1/4 = ? (b) 2/4 = ? (C) 1/2 = ?

lawyer [7]

Answer:

Step-by-step explanation:

A. 1.4. B. 2.4. C. 1.2

8 0

3 years ago

Suppose triangle ABC has vertices at A(1, 0), B(10, 0), and C(2, 6). After a 60° counterclockwise rotation about the origin, ver

Artemon [7]

Check the picture attached.

Let OB be the radius of circle with center O.

Let B' be the image of B after the described rotation

OB and OB' are sides of the equilateral triangle OBB'.

The x coordinate of B' is the midpoint of OB, that is 5.

In the right triangle B', point (5, 0) and B:

Distance point (5, 0) to B is 5
|B'B|=|OB|=10

so by the pythagorean theorem:

$a= \sqrt{ 10^{2} - 5^{2} } = \sqrt{ 2^{2} *5^{2} - 5^{2} }= \sqrt{5^{2}(4-1)}=5 \sqrt{3}$ units

Answer: $5 \sqrt{3}$

3 0

3 years ago

Find all relative extrema of the function. use the second derivative test where applicable. (if an answer does not exist, enter

Alinara [238K]

The given quadratic describes a parabola that opens upward. Its one absolute extreme is a minimum that is found at x = -3/2. The value of the function there is
(-3/2 +3)(-3/2) -1 = -13/4

The one relative extreme is a minimum at (-1.5, -3.25).

_____
For the parabola described by ax² +bx +c, the vertex (extreme) is found where
x = -b/(2a)
Here, that is x=-3/(2·1) = -3/2.