Answer:
The answer is the option C
graph of
minus
, with discontinuity at negative
, negative 
Step-by-step explanation:
we have

Simplify


Step 1
Convert to a factored form the numerator
Group terms that contain the same variable, and move the constant to the opposite side of the equation

Complete the square. Remember to balance the equation by adding the same constants to each side.


Rewrite as perfect squares

Square root both sides




so
Step 2
Simplify the function f(x)

The domain of the function f(x) is all real numbers except the number 
Because the denominator can not be zero
------> with a discontinuity at 

The discontinuity is at point 
the answer in the attached figure