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harkovskaia [24]
3 years ago
5

Classify the following triangles check all that apply

Mathematics
1 answer:
Rudiy273 years ago
3 0

Answer:

A. Scalene since all sides have different lengths

E. Right since it has a right angle

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A factory creates 80 kilograms of steel in 1 hour. How many kilograms does the factory make in 4 hours?
fgiga [73]

Answer:

320

Step-by-step explanation:

80*4

6 0
2 years ago
Factor the Trimonial y to the second +3y-54
Molodets [167]
See the answer below.

6 0
3 years ago
Please help!!!!!!solve
fgiga [73]
I’m a bit confused confused, but the answer may be -2x^3 + 2x^2 - 2x +2

Work:

To solve this, take the equation for q and the equation for r, and multiply them together.

Use the distributive property to multiply them.

I’m not sure if this is right or not, so pls don’t get mad if it isn’t.

Thank you! :)
5 0
3 years ago
How is the series 5+11+17…+251 represented in summation notation?
NISA [10]

Answer:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

Step-by-step explanation:

Given:

  • Series 5+11+17+...+251

To find:

  • Summation notation of the given series

Summation Notation:

\displaystyle \large{\sum_{k=1}^n a_k}

Where n is the number of terms and \displaystyle \large{a_k} is general term.

First, determine what kind of series it is, there are two main series that everyone should know:

  • Arithmetic Series

A series that has common difference.

  • Geometric Series

A series that has common ratio.

If you notice and keep subtracting the next term with previous term:

  • 11-5 = 6
  • 17-11 = 6

Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.

Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:

<u>Arithmetic Sequence</u>

\displaystyle \large{a_n=a_1+(n-1)d}

Where \displaystyle \large{a_n} is the nth term, \displaystyle \large{a_1} is the first term and \displaystyle \large{d} is the common difference:

So for our general term:

\displaystyle \large{a_n=5+(n-1)6}\\\displaystyle \large{a_n=5+6n-6}\\\displaystyle \large{a_n=6n-1}

And for number of terms, substitute \displaystyle \large{a_n} = 251 and solve for n:

\displaystyle \large{251=6n-1}\\\displaystyle \large{252=6n}\\\displaystyle \large{n=42}

Now we can convert the series to summation notation as given the formula above, substitute as we get:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

5 0
2 years ago
If segment LN is congruent to segment NP and ∠1 ≅ ∠2, prove that ∠NLO ≅ ∠NPM:
scoundrel [369]
The missing reason to complete Hector's proof is
<span>Corresponding Parts of Congruent Triangles Are Congruent
It's been established in the previous statement that triangle LNO and triangle PNM are congruent by the AAS Postulate.
The proof
</span>Corresponding Parts of Congruent Triangles Are Congruent
is comprehensive.
4 0
3 years ago
Read 2 more answers
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