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3 years ago

Classify the following triangles check all that apply

Mathematics

1 answer:

Rudiy273 years ago

3 0

Answer:

A. Scalene since all sides have different lengths

E. Right since it has a right angle

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Need help, please.............................

Bogdan [553]

Answer:

i DON'T KNOW THE ANSWER

Step-by-step explanation:

I DONT KNOW THE ANSWER ALL I KNOW IS TO USE BATMAN IF YOU KNOW WHAT THAT IS AND YEAH YOU WILL FIND THE ANSWER

4 0

3 years ago

Find the slope of the line (-1,-4) , (-4,2)

Feliz [49]

Rise = -6
Run = 3

-6/3 = -2

Slope = -2

4 0

3 years ago

What is the slope of the equation y = 3/4x + 8? A. 3/4 B. 8 C. 3 D. 4

steposvetlana [31]

Answer:

Step-by-step explanation:

y = m x + b

y = 3 /4 x − 8

Rewrite in slope-intercept form.

y = 3 /4 x − 8

Using the slope-intercept form, the slope is 3 /4 .

m =3 /4

6 0

3 years ago

Jordan keeps track of rainy days for one year. This year he counted 27 weeks with at least 1 rainy day. How many weeks had no ra

Komok [63]

There are 52 weeks in a year, so subtract 27 from 52.

52-27=25

There were 25 weeks with no rainy days

3 0

4 years ago

Determine the number of possible solutions for a triangle with B=37 degrees, a=32, b=27

vladimir1956 [14]

Answer:

Two possible solutions

Step-by-step explanation:

we know that

Applying the law of sines

$\frac{a}{sin(A)}=\frac{b}{Sin(B)}=\frac{c}{Sin(C)}$

we have

$a=32\ units$

$b=27\ units$

$B=37\°$

step 1

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{Sin(B)}$

substitute the values

$\frac{32}{sin(A)}=\frac{27}{Sin(37\°)}$

$sin(A)=(32)Sin(37\°)/27=0.71326$

$A=arcsin(0.71326)=45.5\°$

The measure of angle A could have two measures

the first measure-------> $A=45.5\°$

the second measure -----> $A=180\°-45.5\°=134.5\°$

step 2

Find the first measure of angle C

Remember that the sum of the internal angles of a triangle must be equal to $180\°$

$A+B+C=180\°$

substitute the values

$A=45.5\°$

$B=37\°$

$45.5\°+37\°+C=180\°$

$C=180\°-(45.5\°+37\°)=97.5\°$

step 3

Find the first length of side c

$\frac{a}{sin(A)}=\frac{c}{Sin(C)}$

substitute the values

$\frac{32}{sin(37\°)}=\frac{c}{Sin(97.5\°)}$

$c=Sin(97.5\°)\frac{32}{sin(37\°)}=52.7\ units$

therefore

the measures for the first solution of the triangle are

$A=45.5\°$ , $a=32\ units$

$B=37\°$ , $b=27\ units$

$C=97.5\°$ , $b=52.7\ units$

step 4

Find the second measure of angle C with the second measure of angle A

Remember that the sum of the internal angles of a triangle must be equal to $180\°$

$A+B+C=180\°$

substitute the values

$A=134.5\°$

$B=37\°$

$134.5\°+37\°+C=180\°$

$C=180\°-(134.5\°+37\°)=8.5\°$

step 5

Find the second length of side c

$\frac{a}{sin(A)}=\frac{c}{Sin(C)}$

substitute the values

$\frac{32}{sin(37\°)}=\frac{c}{Sin(8.5\°)}$

$c=Sin(8.5\°)\frac{32}{sin(37\°)}=7.9\ units$

therefore

the measures for the second solution of the triangle are

$A=45.5\°$ , $a=32\ units$

$B=37\°$ , $b=27\ units$

$C=8.5\°$ , $b=7.9\ units$

6 0

3 years ago