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Hitman42 [59]
3 years ago
10

Please help!!!!!!solve

Mathematics
1 answer:
fgiga [73]3 years ago
5 0
I’m a bit confused confused, but the answer may be -2x^3 + 2x^2 - 2x +2

Work:

To solve this, take the equation for q and the equation for r, and multiply them together.

Use the distributive property to multiply them.

I’m not sure if this is right or not, so pls don’t get mad if it isn’t.

Thank you! :)
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6 0
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Which shapes contain at least one right angle?<br><br> Select each correct answer.
Andrej [43]
1: Trapezoid
2: rectangle!

STEP BY STEP EXPLINATION


A right angle is exactly 90 degrees, so if the pentagon has 108 degree angles, it’s not a right Angle!

The parallelogram has 107 degree angles and 73 degree angles, it’s not exactly 90.
The trapezoid has two right angles! The two sides make a right angle at the vertex! So, it has a right angle!
Same thing for the rectangle!



HOPE THIS HELPS! HAVE A GREAT DAY!
8 0
2 years ago
Read 2 more answers
Simplify and write the trig expression in terms of sin and cos
dsp73

We have:

cot(-x)cos(-x)+sin(-x)=-\frac{1}{f(x)}

Then we use trigonometric identities to change the negative sign of the trigonometric functions, so:

-sin(x)-cot(x)cos(x)=-\frac{1}{f(x)}

We clear f(x):

f(x)=\frac{1}{sin(x)+cot(x)cos(x)}=\frac{1}{sin(x)+\frac{cos(x)}{sin(x)}cos(x)}=\frac{1}{sin(x)+\frac{cos^2(x)}{sin(x)}}

we simply what we can:

f(x)=\frac{1}{\frac{sin^2(x)+cos^2(x)}{sin(x)}}=sin(x)

Thus, the correct answer is;

f(x)=sin(x)

6 0
1 year ago
Which of the following rational functions is graphed below?​
vampirchik [111]

Answer:

The correct option is D.

i.e.

f\left(x\right)=\frac{1}{x\left(x+4\right)} is the correct option.

The correct graph is shown in attached figure.

Step-by-step explanation:

Considering the function

f\left(x\right)=\frac{1}{x\left(x+4\right)}

\mathrm{Domain\:of\:}\:\frac{1}{x\left(x+4\right)}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x

\mathrm{Range\:of\:}\frac{1}{x\left(x+4\right)}:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:-\frac{1}{4}\quad \mathrm{or}\quad \:f\left(x\right)>0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-\frac{1}{4}]\cup \left(0,\:\infty \:\right)\end{bmatrix}

\mathrm{Axis\:interception\:points\:of}\:\frac{1}{x\left(x+4\right)}:\quad \mathrm{None}

\mathrm{Extreme\:Points\:of}\:\frac{1}{x\left(x+4\right)}:\quad \mathrm{Maximum}\left(-2,\:-\frac{1}{4}\right)

So, the correct graph is shown in attached figure.

Therefore, the correct option is D.

i.e.

f\left(x\right)=\frac{1}{x\left(x+4\right)} is the correct option.

7 0
3 years ago
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