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Ede4ka [16]
4 years ago
13

Help help please please

Mathematics
1 answer:
Marat540 [252]4 years ago
5 0

Answer:

For every 3 books adrian read, Paisley read 2 books

Step-by-step explanation:

\frac{21}{14}= \frac{3}{2\\}

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Integrate this for me please
mel-nik [20]
\int\limits_{0}^{\frac{\pi }{6}}tan^2(x)sec^2(x)\cdot dx
\\------------------\\
u=tan(x)\implies \frac{du}{dx}=sec^2(x)\implies \frac{du}{sec^2(x)}=dx
\\------------------\\
\int\limits_{0}^{\frac{\pi }{6}}u^2sec^2(x)\cdot \cfrac{du}{sec^2(x)}\implies 
\int\limits_{0}^{\frac{\pi }{6}}u^2\cdot du
\\ \quad \\


\textit{now, we need to change the bounds as well, so}
\\------------------\\
u(0)=tan(0)\implies 0
\\ \quad \\

u\left( \frac{\pi }{6} \right)=tan\left( \frac{\pi }{6} \right)\implies \frac{1}{\sqrt{3}}
\\------------------\\
thus\implies \int\limits_{0}^{\frac{1 }{\sqrt{3}}}u^2\cdot du

and surely you can take it from there,
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