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3 years ago

Which ordered pair is a solution to this equation? 2x+3y=16 A.) (11, 1)

2 answers:

7 0

<span>C.) (5,2) as we put these values in the above equation we get 16 on both sides and hence the equation is satisfied.if we put values in the above equation the answer is `16. from above equation 2x+3y=16 put x=5 y=2 2(5)+3(3)=16</span>

Sunny_sXe [5.5K]3 years ago

3 0

5,2 is the answer, this is such easy question my baby brother could do it easy

You might be interested in

Find the inverse of f(x)= -x + 3

inna [77]

Let g the inverse function of f.

The most important property of g and f being inverses of each other, is that

g(f(x))=x, also f(g(x))=x

so, what one function 'does' to x, the other 'undoes' it.

Thus, we have:

f(g(x))=x and alos f(g(x))= -g(x)+3, from the rule

thus :

-g(x)+3=x

-g(x)=x-3

g(x)=-x+3

check: f(g(x))=f(-x+3)=-(-x+3)+3=x-3+3=x

Answer: the inverse of f is g, such that g(x)=-x+3

4 0

3 years ago

If VT=2,what is the length of PT?

marusya05 [52]

Step-by-step explanation:

$\underline{ \underline{ \text{Given : }}}$

Perpendicular ( P ) = VT = 2
Base ( b ) = PT
$\theta = \tt{60 \degree}$

$\underline{ \underline{ \text{Solution}}} :$

$\tt{ \tan(60 \degree) = \frac{perpendicualar}{base}}$

⟶ $\tt{ \sqrt{3} = \frac{2}{PT}}$

⟶ $\tt{ \sqrt{3} \: PT= 2}$

⟶ $\tt{PT = \frac{2}{ \sqrt{3}} }$

⟶ $\tt{PT= \boxed{\tt{ \frac{2 \sqrt{3} }{{3} }}}}$

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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6 0

3 years ago

Topic: The Quadratic Formula

Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

$x= \frac{-b +- \sqrt{b^2-4ac} }{2a}$

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² = x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

$x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\= -4 or 1$

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

$x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\$

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

$x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2$

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0

3 years ago

Can you please show working out for $4,000 at 3% for 4 years

dedylja [7]

$100\%+3\%=103\%\\\\p\%=\dfrac{p}{100}\to103\%=\dfrac{103}{100}=1.03\\\\\$4,000\cdot1.03^4=\$4,679.43$

5 0

3 years ago

Pls no one answered this last time :( i want to be free

kipiarov [429]

Answer:

The total area is 3016 square inches, approximately

4 0

3 years ago