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3 years ago

Solve the equation using the method of completing the square. 2x^2 + 16 - 8 = 0

Mathematics

2 answers:

Anna [14]3 years ago

6 0

Answer:

x=-4+-2 to the square root 5

Step-by-step explanation:1) Move the "non X" term to the right:

2x^2+16x-8=0 becomes

2x^2 +16x = +8

2) Divide the equation by the coefficient of X² which in this case is 2

x^2 + 8x = 4

3) Now here's the "completing the square" stage in which we:

• take the coefficient of X (which is 8)

• divide it by 2 [8 / 2 = 4]

• square that number [4^2 = 16]

• then add it to both sides of the equation.

x^2 + 8x + 16 = 20

Take the square root of both sides of the equation:

x + 4 = sq root (20)

x = sq root (20) -4

x1 = 4.472135955 -4

x1 = .472135955

x2 = -4.472135955 -4

x2 = -8.472135955

mamaluj [8]3 years ago

3 0

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=========================================

Work Shown:

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___________________________Please help?

ludmilkaskok [199]

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The given expression is $27x^{4} +15x^{3} +53x^{2}$ .

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one-term polynomial is called a monomial
two-term polynomial is called a binomial and
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