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ikadub [295]
3 years ago
11

You have agreed to loan some money to a friend at a simple interest rate of 140% To make it easy on your friend who never took M

ath 140 you tell him you'll give him some money now and he just needs to pay you back a nice even $700 in 4 weeks. How much money do you hand him? $ (nearest $1)
Mathematics
1 answer:
poizon [28]3 years ago
6 0

Answer:

$500

Step-by-step explanation:

You hand him 100%

He pays back 140%(original amount plus 40%)= 700

Original amount =x

700/140  =  x/100

140x=700*100

140x = 70,000

x=500

200 is the 40% of 500

500+200= 700

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The following dot plots shows the pulse rates of runners after finishing a marathon:
DochEvi [55]

Answer:

c

Step-by-step explanation:

7 0
3 years ago
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Use synthetic division to solve (2x^3 + 4x^2 -35x +15) + (x-3). What is the quotient?
kow [346]

The quotient is: 2x^2+10x-5

The remainder is: 0

Step-by-step explanation:

Solve using synthetic division:

(2x^3 + 4x^2 -35x +15) \div (x-3)

The division is shown in figure attached.

The quotient is: 2x^2+10x-5

The remainder is: 0

Keywords: Synthetic division

Learn more about Synthetic division at:

  • brainly.com/question/10941043
  • brainly.com/question/629998
  • brainly.com/question/5022643

#learnwithBrainly

6 0
4 years ago
Read 2 more answers
Verify that the points are the vertices of a parallelogram and find its area. (2,-1,1), (5, 1,4), (0,1,1), (3,3,4)
AfilCa [17]

Answer:

Verified

Area = 13.12 square units.

Step-by-step explanation:

Let the given points / vertices of the parallelogram be represented as follows:

A(2,-1,1),

B(5, 1,4),

C(0,1,1),

D(3,3,4)

In vector notation, we can have;

A = 2i - j + k

B = 5i + j + 4k

C = 0i + j + k

D = 3i + 3j +4k

One of the ways to prove that a quadrilateral is a parallelogram is to show that both pairs of opposite sides are parallel.

(i) Now, let's find the various sides of the assumed parallelogram. These sides are:

AB = B - A = [5i + j + 4k] - [2i - j + k]            <em>open the brackets</em>

AB = 5i + j + 4k - 2i + j - k                            <em>collect like terms and solve</em>

AB = 5i - 2i + j  + j - k + 4k

AB = 3i + 2j+ 3k

BC = C - B = [0i + j + k] - [5i + j + 4k]            <em>open the brackets</em>

BC = 0i + j + k - 5i - j - 4k                             <em>collect like terms and solve</em>

BC = 0i - 5i + j  - j + k - 4k

BC = -5i + 0j - 3k

CD = D - C = [3i + 3j +4k] - [0i + j + k]            <em>open the brackets</em>

CD = 3i + 3j + 4k - 0i - j - k                             <em>collect like terms and solve</em>

CD = 3i - 0i + 3j  - j + 4k - k

CD = 3i + 2j + 3k

DA = A - D = [2i - j + k] - [3i + 3j +4k]            <em>open the brackets</em>

DA = 2i - j + k - 3i - 3j - 4k                             <em>collect like terms and solve</em>

DA = 2i - 3i  - j  - 3j + k - 4k

DA = - i - 4j - 3k

AC = C - A = [0i + j + k] - [2i - j + k]            <em>open the brackets</em>

AC = 0i + j + k - 2i + j - k                             <em>collect like terms and solve</em>

AC = 0i - 2i  + j  + j + k - k

AC = - 2i + 2j +0k

BD = D - B = [3i + 3j + 4k] - [5i + j + 4k]            <em>open the brackets</em>

BD = 3i + 3j + 4k - 5i - j - 4k                             <em>collect like terms and solve</em>

BD = 3i - 5i  + 3j  - j + 4k - 4k

BD = - 2i + 2j + 0k

(ii) From the results in (i) above, it has been shown that;

AB is equal to CD, and that implies that AB is parallel to CD. i.e

AB = CD => AB || CD

<em>Also,</em>

AC is equal to BD, and that implies that AC is parallel to BD. i.e

AC = BD => AC || BD

(iii) Therefore, ABDC is a parallelogram since its opposite sides are equal and parallel.

(B) Now let's calculate the area of the parallelogram.

To calculate the area, we find the magnitude of the cross product between any two adjacent sides.

In this case, we choose sides AC and AB.

Area = | AC x AB |

Where;

AC X AB = \left[\begin{array}{ccc}i&j&k\\-2&2&0\\3&2&3\end{array}\right]

AC X AB = i(6 - 0) - j(-6 - 0) + k(-4 -6)

AC X AB = 6i + 6j - 10k

|AC X AB| = \sqrt{6^2 + 6^2 + (-10)^2} \\

|AC X AB| = \sqrt{36 + 36 + 100} \\

|AC X AB| = \sqrt{172} \\

|AC X AB| = 13.12

Therefore the area is 13.12 square units.

PS: The diagram showing this parallelogram has been attached to this response.

7 0
3 years ago
Hello, help me please))
Fed [463]

Answer:

  • 6
  • 9
  • 1/8
  • -10/11

Step-by-step explanation:

You can rewrite the given log expressions to express them in terms of ln(a), ln(b), and ln(c). Then substituting the given values will produce the value of the expression.

Or, you can define the variables 'a', 'b', and 'c' and let your calculator compute these directly.

__

<h3>1.</h3>

  \ln\left(\dfrac{a^4}{b^4c^{-2}}\right)=4\ln(a)-(4\ln(b)-2\ln(c))=4\cdot2-4\cdot3+2\cdot5=\boxed{6}

<h3>2.</h3>

  \ln\left(\sqrt{b^{-2}c^4a^2}\right)=\dfrac{1}{2}\left(-2\ln(b)+4\ln(c)+2\ln(a)\right)=\ln(a)-\ln(b)+2\ln(c)\\\\=2-3+2\cdot5=\boxed{9}

<h3>3.</h3>

  \dfrac{\ln(a^1b^2)}{\ln(bc)^2}=\dfrac{\ln(a)+2\ln(b)}{(\ln(b)+\ln(c))^2}=\dfrac{2+2\cdot3}{(3+5)^2}=\dfrac{8}{64}=\boxed{\dfrac{1}{8}}

<h3>4.</h3>

  \ln(c^{-2})\left(\ln\dfrac{a}{b^{-3}}\right)^{-1}=\dfrac{-2\ln(c)}{\ln(a)-(-3)\ln(b)}=\dfrac{-2(5)}{2+3\cdot3}=\boxed{-\dfrac{10}{11}}

_____

The applicable rules of logarithms are ...

  • ln(ab) = ln(a) +ln(b)
  • ln(a/b) = ln(a) -ln(b)
  • ln(a^b) = b·ln(a)
  • ln(a) = b  ⇔  a = e^b

Of course, a square root is the same as a 1/2 power.

7 0
2 years ago
Given 2x² = -8, x is
DanielleElmas [232]

Answer:

2x²=-8

x²= 8/2

x²= 4

x= √4

x= 2

So, the value of x is 2

8 0
4 years ago
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