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kompoz [17]
3 years ago
7

Help Please!!!!!

Mathematics
1 answer:
GrogVix [38]3 years ago
7 0
X ≥ 90 + 3x 
You simplify the right side, then subtract 180 from both sides, then multiply by negative one.
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If 3 bars of chocolate cost $15.00 ghana cedis how much will 7 bars cost ratio
Rudiy27

Answer:

7 chocolate bars will cost $35

Step-by-step explanation:

if 3 cost $15 then 1 bar would cost 5 dollars and 5x7=35

here is a ratio:

<u>3</u> = <u>7</u>

15 = 35

6 0
3 years ago
A proportional relationship between the number of pounds of cabbage (x) and the price in dollars (y) is graphed, and the ordered
Marta_Voda [28]

Answer: A. 1 pound of cabbage will cost 40 cents.  B. (10,4) means that 10 pounds of cabbage will cost 4 dollars.

Step-by-step explanation:

If it is proportional that means the y value divided by the x value will give you a constant slope.

So using that use the coordinates (5,2)  to find the cost of 1 pound of cabbage.

2/5 = 0.4

so you could write the equation y= 0.4x  where x is the number of pound.

Part A:     y= 0.4(1)    

                y= $0.40  which means one pound of cabbage will cost 40 cents.

Part B.    (10,4) in this case it will means that for 10 pounds of cabbage it will cost $4.

   Plot it into the equation and find out

 in the coordinates (10,4) 4 is the y and 10 is the x

   4= 0.4(10)

  4= 4  

Which means it true that 10 pounds of cabbage will cost 4 dollars.

5 0
3 years ago
The equation of the line in the graph is y= (blank) x+ (blank)
VashaNatasha [74]
Y= -1x + -1 is the answer
7 0
3 years ago
A survey of 200 families showed that
KengaRu [80]

Answer:

15 is the answer , the total people who has dogs , cats , parakeets and none is equals to <u>185</u> then from 200 you minus 185 which is 15 so 15 people had parakeets only

4 0
3 years ago
What is the solution of -5x &gt; 25?
Veseljchak [2.6K]
<span>Divide both sides by -5.
</span><span><span>−<span>5x /</span></span><span>−5  </span></span>>  <span>25 /<span>−<span>5


ANSWER: X < - 5

</span></span></span>
4 0
3 years ago
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