53b−7b−6b+1 if b=25 Please help me with this problem! And what is the simplified expression?

Mathematics

1 answer:

Nataly_w [17]3 years ago

7 0

You have to substitute 25 for b to simplify the expression.

53(25) -7(25) -6(25) +1
=1325 - 175 - 150 +1
=1001

You might be interested in

Divide using synthetic division. ( x^4-12x^2-9)/(x+3)

Firdavs [7]

Answer:

x^3 - 3x^2 - 3x + 9 + (-36/(x+3))

x^3 - 3x^2 - 3x + 9 - (36/(x+3))

Step-by-step explanation:

First set the divisor equal to 0:

x + 3 = 0

Subtract 3 from both sides

x = -3

This is what you'll divide the dividend by in synthetic division.

Take the coefficents of each term in the dividend. Do not forget the 0 placeholders:

x^4 + 0x^3 - 12x^2 + 0x -9

Coefficents: 1. 0. -12. 0 -9.

Please see the image for the next steps.

The remainder is -36. Put the remainder over the divisor and add it to the polynomial (shown in image)

-36/(x+3)

6 0

3 years ago

Partners A, B and C share the profit of a business deal. Partner A gets 1/6, Partner B gets 3/4 and Partner C gets €25. How much

34kurt

That is the answer. Hope it helps

8 0

3 years ago

If the function f(x)=-1/2x-7 were graphed, which of the following would be true? A. The y-values would be negative. B. As the x-

vagabundo [1.1K]

f(x)= -1/2x-7 (better expressed as f(x) = (-1/2)x - 7 ) has a negative slope, so as x increases, y decreases. Answer D is correct.

3 0

3 years ago

Read 2 more answers

Will mark brainliest! Questions are in the picture!

alexdok [17]

Answer:

52.9 inches .

Step-by-step explanation:

Given that the triangular indentation has an area of 100 in.² and the base and height of this traingle are represented by expressions 3x and x+3 respectively . We need to find out the perimeter to the nearest tenth.

As we know that the area of triangle is ,

$\rm\longrightarrow Area_{\triangle}=\dfrac{1}{2}(base)(height)$

Substituting the respective values,

$\rm\longrightarrow 100\ =\dfrac{1}{2}(x+3)(3x)\\\\\rm\longrightarrow 2(100) = 3x(x+3)\\\\\rm\longrightarrow200 = 3x^2+9x\\\\\rm\longrightarrow 3x^2+9x-200=0$

On using the Quadratic formula , we have;

$\rm\longrightarrow x =\dfrac{-9\pm\sqrt{9^2-4(3)(-200)}}{2(3)} \\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{81+1200}}{6}\\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{1281}}{6}$