Complete Question
The complete question is shown on the first uploaded image
Answer:
First question
![Ab_1 = \left[\begin{array}{ccc}{-1}&{3}\\ 1 &4 \\5 &8\end{array}\right]\left[\begin{array}{ccc}5\\-2\\\end{array}\right]](https://tex.z-dn.net/?f=Ab_1%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B-1%7D%26%7B3%7D%5C%5C%201%20%264%20%5C%5C5%20%268%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C-2%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Second question
![Ab_1 = \left[\begin{array}{ccc}{-1}&{3}\\ 1 &4 \\5 &8\end{array}\right]\left[\begin{array}{ccc}5\\-2\\\end{array}\right] = \left[\begin{array}{ccc}{(-1 * 5 )+ (3* -2)}\\{(1 * 5)+ (4 * -2)}\\{(5 * 5) + (8*-2)}\end{array}\right] = \left[\begin{array}{ccc}{-11}\\{-3}\\{29}\end{array}\right]](https://tex.z-dn.net/?f=Ab_1%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B-1%7D%26%7B3%7D%5C%5C%201%20%264%20%5C%5C5%20%268%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C-2%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B%28-1%20%2A%205%20%29%2B%20%283%2A%20-2%29%7D%5C%5C%7B%281%20%2A%205%29%2B%20%284%20%2A%20-2%29%7D%5C%5C%7B%285%20%2A%205%29%20%2B%20%288%2A-2%29%7D%5Cend%7Barray%7D%5Cright%5D%20%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B-11%7D%5C%5C%7B-3%7D%5C%5C%7B29%7D%5Cend%7Barray%7D%5Cright%5D)
Third question
![Ab_1 = \left[\begin{array}{ccc}{-1}&{3}\\ 1 &4 \\5 &8\end{array}\right]\left[\begin{array}{ccc}-3\\4\\\end{array}\right]](https://tex.z-dn.net/?f=Ab_1%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B-1%7D%26%7B3%7D%5C%5C%201%20%264%20%5C%5C5%20%268%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%5C%5C4%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Fourth question
![Ab_1 = \left[\begin{array}{ccc}{-1}&{3}\\ 1 &4 \\5 &8\end{array}\right]\left[\begin{array}{ccc}-3\\4\\\end{array}\right] = \left[\begin{array}{ccc}{(-1 * -3 )+ (3* 4)}\\{(1 * -3)+ (4 * 4)}\\{(5 * -3) + (8*4)}\end{array}\right] = \left[\begin{array}{ccc}{15}\\{13}\\{-23}\end{array}\right]](https://tex.z-dn.net/?f=Ab_1%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B-1%7D%26%7B3%7D%5C%5C%201%20%264%20%5C%5C5%20%268%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%5C%5C4%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B%28-1%20%2A%20-3%20%29%2B%20%283%2A%204%29%7D%5C%5C%7B%281%20%2A%20-3%29%2B%20%284%20%2A%204%29%7D%5C%5C%7B%285%20%2A%20-3%29%20%2B%20%288%2A4%29%7D%5Cend%7Barray%7D%5Cright%5D%20%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B15%7D%5C%5C%7B13%7D%5C%5C%7B-23%7D%5Cend%7Barray%7D%5Cright%5D)
Fifth question
The correct option is A
Step-by-step explanation:
From the question we are told that
The matrix A is ![A = \left[\begin{array}{ccc}{-1}&{3}\\ 1 &4 \\5 &8\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B-1%7D%26%7B3%7D%5C%5C%201%20%264%20%5C%5C5%20%268%5Cend%7Barray%7D%5Cright%5D)
The matrix B is ![B = \left[\begin{array}{ccc}5&{-3}\\{-2}&4\end{array}\right]](https://tex.z-dn.net/?f=B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26%7B-3%7D%5C%5C%7B-2%7D%264%5Cend%7Barray%7D%5Cright%5D)
The first question is to set up the product 
, where 
is the first column of matrix B, this shown as
The second question is to calculate , this is evaluated as
The third question is to set up the product 
, where 
is the second column of matrix B, this shown as
The fourth question is to calculate , this is evaluated as
The fifth question is to determine the numerical expression for the first entry in the first column of AB using the row-column rule and from the calculation of we see that it is
Answer:
91
Step-by-step explanation:
I just Multiplied 13 x 7 to get 91... I hope it helps but if its wrong I am very sorry
Answer:
Width of the box = 18.97 inches
Step-by-step explanation:
Length of the bat = 36 inches.
That means length of the diagonal of the bat (BC) = 36 inches
By applying Pythagoras theorem in right triangle BDC,
BC² = BD² + CD²
BC² = (30)² + w² -------(1)
BY applying Pythagoras theorem in right triangle ABC,
AC² = AB² + BC²
(36)² = 6² + BC²
By substituting the value of BC from equation (1),
(36)² = 6² + (30)² + w²
1296 = 36 + 900 + w²
w² = 1296 - 936
w = √360
w = 18.97 inches
Answer:
First step
Step-by-step explanation:
Subtract the 4 to the other side making the equation
(12x+8)+4=3
12x+8=-1
12x=-9
x=-3/4
Answer:
2500
Step-by-step explanation:
a² + 2ab + b²
49² + 98 + 1
Comparing terms
a²= 49²
a= 49
2ab = 98
2× 49 × b = 98
98b = 98
b= 98/98
b = 1
or
b²= 1
b=√1
b= 1
a=49 and b= 1
Hence (a+b)²= (49+1)²
50²= 2500
